Gm mol. wt. of HCl = 1 + 35.5 = 36.5 g
36.5 g of HCl = 6.023 × 1023 number of molecules
Therefore, 109.5 g of HCl = 6.023 × 10^{23}\over 36.5×109.5
= 109.5\over 36.5×6.023 × 1023
Hence, number of molecules in 109.5 g of HCl is 3 × 6.023 x 1023
Gm mol. wt. of HCl = 1 + 35.5 = 36.5 g
36.5 g of HCl = 6.023 × 1023 number of molecules
Therefore, 109.5 g of HCl = 6.023 × 10^{23}\over 36.5×109.5
= 109.5\over 36.5×6.023 × 1023
Hence, number of molecules in 109.5 g of HCl is 3 × 6.023 x 1023
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