How does the electric flux due to a point charge enclosed by a spherical Gaussian surface get affected when its radius is increased? [CBSE Delhi 2016]

The electric flux through a Gaussian surface, enclosing the charge q is φE = {q\over \varepsilon_0 }

This is independent of the radius of the Gaussian surface, so if the radius is increased, the electric flux through the surface will remain unchanged.

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