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Question

Identify the oxidizing agent (oxidant) in the following reactions. (i) Pb3O4 + 8HCL → 3PbCl2 + Cl2 + 4H2O (ii) 2Mg + O2 → 2MgO (iii) CuSO4 + Zn → Cu + ZnSO4 (iv) V2O5 + 5Ca → 2V + 5CaO (v) 3Fe + 4H2O → Fe3O4 + 4H2 (vi) CuO + H2 → Cu + H2O

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Answer

An oxidizing agent is a substance that gains electrons and gets reduced in a chemical reaction.

(i) Pb₃O₄ + 8HCl → 3PbCl₂ + Cl₂ + 4H₂O

  • Oxidizing Agent: Pb₃O₄ (Lead(IV) oxide)
  • Reason: Pb₃O₄ gets reduced to PbCl₂ while oxidizing Cl⁻ to Cl₂.

(ii) 2Mg + O₂ → 2MgO

  • Oxidizing Agent: O₂ (Oxygen gas)
  • Reason: O₂ gains electrons and gets reduced to O²⁻ in MgO.

(iii) CuSO₄ + Zn → Cu + ZnSO₄

  • Oxidizing Agent: CuSO₄ (Copper(II) sulfate)
  • Reason: Cu²⁺ in CuSO₄ gains electrons and gets reduced to Cu.

(iv) V₂O₅ + 5Ca → 2V + 5CaO

  • Oxidizing Agent: V₂O₅ (Vanadium(V) oxide)
  • Reason: V₂O₅ gets reduced to vanadium metal (V).

(v) 3Fe + 4H₂O → Fe₃O₄ + 4H₂

  • Oxidizing Agent: H₂O (Water)
  • Reason: H₂O provides oxygen, which oxidizes Fe to Fe₃O₄ while itself getting reduced to H₂.

(vi) CuO + H₂ → Cu + H₂O

  • Oxidizing Agent: CuO (Copper(II) oxide)
  • Reason: CuO gets reduced to Cu while oxidizing H₂ to H₂O.

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