On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?

Question

On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?

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Answer

For both the stones

Initial velocity, u = 0

Acceleration in downward direction = g

Now, h = {ut+{1\over 2}\ gt^2}

⟹    h = {0 +{1\over2}\ gt^2}

⟹   h = {{1\over2}\ gt^2}

⟹  t = \sqrt{2h \over g}

Both stones will take the same time to reach the ground because the two stones fall from the same height.

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Velocity-time graph for the ball’s motion is shown in figure.

Observe the graph and answer the following questions. Assume that g = 10 m/s2 and that there is no air resistance. (a) In which direction is the ball moving at point C? (b) At which point is the ball stationary? (c) At which point is the ball at its maximum height? (d) what is the ball’s acceleration at point C? (e) What is the ball’s acceleration at point A? (f) What is the ball’s acceleration at point B? (g) At which point does the ball have the same speed as when it was thrown?

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