Expression for kinetic energy

Ek= ½ mv^{2}

m = Mass of object

v = Velocity of the object in ms^{−1}

Given that kinetic energy, E_{k}=25J

(i) If the velocity of an object is doubled, then v = 5 × 2 = 10 ms^{−1} .

Therefore, its kinetic energy becomes 4 times its original value, because it is proportional to the square of the velocity.

Hence, kinetic energy = 25 × 4 = 100 J.

(ii) If velocity is increased three times, then its kinetic energy becomes 9 times its original value, because it is proportional to the square of the velocity. Hence, kinetic energy = 25 × 9 = 225 J.80