As u = 0,
h1 ={1\over2} 𝑔𝑡_1^2
h2 ={1\over2} 𝑔𝑡_2^2
or, {t_1\over t_2} = \sqrt{h_1 \over h_2}
Ratio will not change in either case because acceleration remains the same. In case of free fall acceleration does not depend upon mass and size
Observe the graph and answer the following questions. Assume that g = 10 m/s2 and that there is no air resistance. (a) In which direction is the ball moving at point C? (b) At which point is the ball stationary? (c) At which point is the ball at its maximum height? (d) what is the ball’s acceleration at point C? (e) What is the ball’s acceleration at point A? (f) What is the ball’s acceleration at point B? (g) At which point does the ball have the same speed as when it was thrown?