As u = 0,
h1 ={1\over2} 𝑔𝑡_1^2
h2 ={1\over2} 𝑔𝑡_2^2
or, {t_1\over t_2} = \sqrt{h_1 \over h_2}
Ratio will not change in either case because acceleration remains the same. In case of free fall acceleration does not depend upon mass and size
As u = 0,
h1 ={1\over2} 𝑔𝑡_1^2
h2 ={1\over2} 𝑔𝑡_2^2
or, {t_1\over t_2} = \sqrt{h_1 \over h_2}
Ratio will not change in either case because acceleration remains the same. In case of free fall acceleration does not depend upon mass and size
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