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ToggleFactorial
For any natural number n, we define factorial as
n! = n(n-1)(n-2)…3×2×1
Important Results Related to Factorial
- 0! = 1! = 1
- Factorials of negative integers and fractions are not defined.
- n! = n(n-1)! = n(n-1)(n-2)!
Permutations
The number of ways of arranging n distinct objects taking some or all of a number of things is called a permutation.
P(n, r) = nPr = n!\over (n-r)!
Properties of permutation
- nPn = n(n-1)(n-2) …. 3×2×1
- nPo = n!\over n!
- nPo = n
- nPn – 1 = n!
- n – 1 Pr + r. n – 1 Pr – 1 = nPr
- {{^nP_r}\over{^nP_{r-1}}}=n-r+1
Important Results on Permutation
- The number of permutations of n different things taken r at a time, when each thing may be repeated any number of times is nr.
- The number of permutations of n things taken all at a time, in which p are alike of one kind, q are alike of the second kind and r are alike of the third kind and rest are different is
n!\over p!q!r!
Restricted Permutations
(i) Number of permutations of n different things taken r at a time,
- When a particular thing is to be included in each arrangement is r.n-1Pr-1.
- When a particular thing is always excluded is n-1Pr.
(ii) Number of permutations of n different objects taken r at a time in which m particular object are always
- excluded = n-mPr
- included = n-mPr-m × r!
(iii) Number of permutations of n different things taken all at a time, when m specified things always come together is m!(n – m + 1)!
Circular Permutations
A circular permutation is an arrangement of objects in a circle, where the order of the objects is important but the starting position is not.
- The number of circular permutations of n different things taken all at a time is (n-1)!. If clockwise and anticlockwise orders are taken as different.
- The number of circular permutations of n different things taken all at a time when clockwise and anticlockwise orders are not taken as different = {1\over2} (n-1)!
Combination
A combination is a selection of items from a set where the order of the selection does not matter.
C (n, r) or nCr = n!\over r!(n - r)! 0≤ r ≤ n
Properties of combination
- nCo = nCn = 1
- nC1 = n
- nCr = nCn-r
- If nCa = nCb, then either a = b or a + b = n
- nCr = ^nP_r\over r!
- nCr + nCr – 1 = n+1Cr
- { {^n}C_r \over{^{n-1}}C_{r-1}}={n\over r}
- { {^n}C_r \over{^{n}}C_{r-1}}={n-r+1\over r}
- nC0 + nC1 + nC2 + nC3 + … + nCn = 2n
- nC0 + nC2 + nC4 + … = nC1 + nC3 + nC5 + … = 2n-1
The important result on the combination
- The number of combinations of n different things have taken r at a time allowing repetitions is n+r-1Cr.
- The total number of combinations of n different objects taken r at a time in which
(a) m particular objects are excluded = n-mCr
(b) m particular objects are included = n-mCr-m
Selection from different Items
- The number r of ways of selecting at least one item from n distinct items is 2n-1.
- The number of ways of answering one or more of n questions is 2n – 1.
- The number of ways of answering one or more of n questions when each question has an alternative = 3n-1.
Division into groups
- The number of ways in which (n+m) different things can be divided into two groups which m and n things respectively = (m+n)!\over m!n!, where m ≠ n
- The number of ways of dividing 2n different elements into two groups of n objects each is (2n)!\over (n!)^2, when the distinction can be made between the groups.
- The number of ways of dividing 2n different elements into two groups of n objects when no distinction can be made between the groups = (2n)!\over 2(n!)^2