Question
How many gram of HCl will be required to completely neutralize 80 g of NaOH ? (H. = 1, O 16, Na 23, Cl = 35.5)
Answer
The balanced chemical equation for the reaction between HCl and NaOH is:
HCl + NaOH → NaCl + H2O
The molar mass of NaOH is 40 g/mol. Therefore, 80 g of NaOH is equal to 2 moles of NaOH.
The equation shows that 1 mole of HCl reacts with 1 mole of NaOH. Therefore, 2 moles of HCl are required to neutralize 2 moles of NaOH.
The molar mass of HCl is 36.5 g/mol. Therefore, 2 moles of HCl is equal to 73 g of HCl.
Hence, 73 g of HCl will be required to completely neutralize 80 g of NaOH.
