Question
A force of 10 N-acting on a body at an angle of 30° with the horizontal direction displaces it horizontally through a distance of 6 m. Calculate the work done. [Ans. 30 √3 J]
Answer
Force (F) = 10 N
Displacement (s) = 6 m
Angle (θ) = 30°
Work (W) = Force (F) × Displacement (s) cos θ
= 10 × 6 × cos 30°
= 60 × √3 \over 2
= 30 √3 J