Question

If the length, breadth and volume of a cuboidal room are 8 m, 6 m and 192 cubic m respectively, then let us calculate the height of the room and the area of four walls of the room.

January 1, 2024

Answer

Length (l) = 8 m; Breadth (b) = 6 m; Volume (V) = 192 cu cm

According to the problem,

8 × 6 × h = 192

h $=\frac{192}{8 × 6}$ = 4

∴ Area of the 4 walls of the room = 2 × (8+6) × 4

= 2 × 14 × 4 sq m = 112 sq m

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