Let the depth of the hole = x m.
Volume of earth removed from the hole = 27 × 18.2 × x cum.
According to the problem,
27 × 18.2 × x = 48 × 31.5 × 0.65
∴ x=\frac{48 × 31.5 × 0.65}{27 × 18.2} m
=\frac{48 × 315 × 65}{27 × 182 × 100} = 2 m .
∴ Depth of the hole = 2 m.