Weight of rice inside the box = (880.5-115.5) kg. = 765 kg.
Volume of the box =\frac{765}{1.5}= 510 cu. dcm.
Let the height of the box = h dcm.
According to the problem,
12 × 8.5 × h = 510
h =\frac{510}{12 × 8.5} = 5 dcm.
Outside length of the box = (12+2 × 0.5) = 13 dcm.
Outside breadth of the box = (8.5+2 × 0.5) = 9.5 dcm.
Outside height of the box =(5+2 × 0.5)=6 dcm.
Total outside surface area of the box
= 2(13 × 9.5+13 × 6+9.5 × 6) sq. dcm.
= 2(123.5+78+57) = 2 × (258.5) = 517 sq. dcm.
∴ Total cost for painting the outside surface area
= 517 × Rs. 1.50 = Rs. 775.50