Question

The time period of two pendulums of length 1 m and 16 m are in ratio : (1) 1 : 16 (2) 1 : 4 (3) 16 : 1 (4) 4 : 1

February 5, 2024

Answer

1 : 4

Reason

As T ∝ √l

T₁/T₂ = √l₁/√l₂

T₁/T₂ = √1 / √16

T₁/T₂ = 1 / 4

T₁: T₂ = 1 : 4

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