Flash Education

Question

A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. Calculate: (i) the velocity acquired by the body, and (ii) change in momentum of the body.

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Answer

Given,

Force (F) = 10 N

Mass (m) = 2 kg

time (t) = 3 s

Initial velocity (u) = 0

we know,

Force (f) = mass (m) × acceleration (a)

10 = 2 × a

or, a = 10/2

or, a = 5

Hence,

Acceleration produced by the body = 5 m s-2

(i) v = u + at

Substituting the values in the formula above we get,

v = 0 + 5 × 3 = 15 m s-1

Hence, velocity of the body is 15 m s-1

(ii) Initial momentum = mu = 2 × 0 = 0

Final momentum = mv = 2 × 15 = 30 kg m s-1

As we know,

Change in momentum = Final momentum – Initial momentum

Change in momentum = 30 – 0 = 30 kg m s-1

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