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Question

A force acts for 10 s on a stationary body of mass 100 kg after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate (i) the velocity acquired by the body, (ii) the acceleration produced by the force, and (iii) the magnitude of the force.

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Answer

(i) velocity (v) = distance/time

= 100/5 = 20 m s-1

(ii) Given,

distance (s) = 100 m

Initial velocity (u) = 0

Final velocity (v) = 20 m s-1

we know,

v2 – u2 = 2as

Hence, a = 2 m s-2

(iii) Given,

mass (m) = 100 kg

acceleration (a) = 2 m s -2

we know,

Force (F) = mass (m) x acceleration (a)

= 100 × 2 = 200 N

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