Question

Action and reaction act on the — (a) same body in opposite directions (b) different bodies in opposite directions (c) different bodies, but in the same direction (d) same body in the same direction

March 14, 2024

Answer

(b) different bodies in opposite directions

Reason — As per the Newton’s third law of motion —

In an interaction of two bodies A and B, the magnitude of the reaction (i.e., the force F_AB applied by body A) is equal in magnitude to the action (i.e., the force F_BA applied by body A on body B), but they are in directions opposite to each other.

💡 Some Related Questions

A ball is thrown vertically upwards from the top of a tower with an initial velocity of 19.6 m s-1. The ball reaches the ground after 5 s. Calculate: (i) the height of the tower, (ii) the velocity of ball on reaching the ground. Take g = 9.8 m s-2

A pebble is dropped freely in a well from it’s top. It takes 20 s for the pebble to reach the water surface in the well. Taking g = 10 m s-2 and speed of sound = 330 m s-1, find: (i) the depth of water surface, and (ii) the time when echo is heard after the pebble is dropped.

A stone is dropped freely from the top of a tower and it reaches the ground in 4 s. Taking g = 10 m s-2, calculate the height of the tower.

A ball is thrown vertically upwards with an initial velocity of 49 m s-1. Calculate: (i) the maximum height attained, (ii) the time taken by it before it reaches the ground again. (Take g = 9.8 m s-2)

A body falls from the top of a building and reaches the ground 2.5 s later. How high is the building ? (Take g = 9.8 m s-2)

(a) How long will a stone take to fall to the ground from the top of a building 80 m high and (b) what will be the velocity of the stone on reaching the ground ? (Take g = 10 m s-2 )

A pebble is thrown vertically upwards with a speed of 20 m s-2. How high will it be after 2 s ? (Take g = 10 m s-2)

A ball is thrown vertically upwards. It returns 6 s later. Calculate (i) the greatest height reached by the ball, and (ii) the initial velocity of the ball. (Take g = 10 m s-2 )

A body is dropped from the top of a tower. It acquires a velocity 20 m s-1 on reaching the ground. Calculate the height of the tower. (Take g = 10 m s-2)

A ball is thrown vertically upwards. It goes to a height 20 m and then returns to the ground. Taking acceleration due to gravity g to be 10 m s-2 find — (a) the initial velocity of the ball (b) the final velocity of the ball on reaching the ground and (c) the total time of journey of the ball.