Work done is given by the formula:
W = F × S Cos θ
Coolie Y is moving the load on a frictionless horizontal platform. The force acting on the load is the force of gravity. In case of Coolie Y as the platform is horizontal so the angle between force and displacement is 90°.
Work done by Coolie Y = F × S Cos 90° = F x S x 0 = 0.
Therefore Coolie Y does zero work.
Coolie X is moving the load on a slope. Assuming the angle of slope as θ:
Work done by Coolie X = F × S Cos θ
Therefore, work done by coolie X is more than coolie Y.
(a) Calculate the change in the gravitational potential energy of the skier between A and B. (b) If 75% of the energy in part (a) becomes the kinetic energy at B, calculate the speed at which the skier arrives at B.(Take g = 10 ms-2).