Velocity of first body v1 = v
Velocity of second body, v2 = 2v
As the mass of the two bodies are same and as kinetic energy is directly proportional to the square of the velocity (K α v2)
Hence, ratio of their kinetic energies is
K_1\over K_2 = (v_1)^2\over (v_2)^2
⇒ K_1\over K_2 = (v)^2\over (2v)^2
⇒K_1\over K_2 = v^2\over 4v^2
⇒ K_1\over K_2 = 1\over 4
(a) Calculate the change in the gravitational potential energy of the skier between A and B. (b) If 75% of the energy in part (a) becomes the kinetic energy at B, calculate the speed at which the skier arrives at B.(Take g = 10 ms-2).