We know that,
KE = 1\over 2 × m × v2
Hence, KE ∝ v2
So we get, KE_1\over KE_2 = v^2_1\over v^2_2
⇒ KE_1\over KE_2 = (15\over 45)2
⇒ KE_1\over KE_2 = (1\over 3)2
⇒ KE_1\over KE_2 = 1\over 9
We know that,
KE = 1\over 2 × m × v2
Hence, KE ∝ v2
So we get, KE_1\over KE_2 = v^2_1\over v^2_2
⇒ KE_1\over KE_2 = (15\over 45)2
⇒ KE_1\over KE_2 = (1\over 3)2
⇒ KE_1\over KE_2 = 1\over 9
(a) Calculate the change in the gravitational potential energy of the skier between A and B. (b) If 75% of the energy in part (a) becomes the kinetic energy at B, calculate the speed at which the skier arrives at B.(Take g = 10 ms-2).