A ball of mass 0.20 kg is thrown vertically upwards with an initial velocity of 20 ms<sup>-1</sup>. Calculate the maximum potential energy it gains as it goes up.

Mass = 0.20 kg Initial velocity = 20ms-1 KE = 1\over 2 × mass × (velocity)2 = 1\over 2 × 0.20 × (20)2 = 1\over 2 × 0.20 × 400 = 40 J ∴ Maximum potential energy at the maximum height = Initial kinetic energy = 40 J

Question

A ball of mass 0.20 kg is thrown vertically upwards with an initial velocity of 20 ms^-1. Calculate the maximum potential energy it gains as it goes up.

April 24, 2024

Answer

Mass = 0.20 kg

Initial velocity = 20ms^-1

KE = $1\over 2$ × mass × (velocity)²

= $1\over 2$ × 0.20 × (20)²

= $1\over 2$ × 0.20 × 400

= 40 J

∴ Maximum potential energy at the maximum height = Initial kinetic energy = 40 J

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A ball of mass 0.20 kg is thrown vertically upwards with an initial velocity of 20 ms-1. Calculate the maximum potential energy it gains as it goes up.

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A ball of mass 0.20 kg is thrown vertically upwards with an initial velocity of 20 ms^-1. Calculate the maximum potential energy it gains as it goes up.