Vol of CO = 50 cc and H2 = 50 cc [As Water gas contains CO and H2 in equal ratio] and O2 = 100 cc
[By Lussac’s law]
CO + H2 + O2 → CO2 + H2O
1 vol : 1 vol : 1 vol → 1 vol : 1 vol
To calculate the amount of O2 used,
CO : O2
1 vol : 1 vol
50 cc : x cc
As ratio between CO and O2 is same so, O2 used is 50 cc.
Hence, remaining O2 = 100 – 50 = 50 cc.
To calculate the amount of CO2 produced,
CO : O
1 vol : 1 vol
50 cc : y cc
Hence, CO2 produced = 50 cc.
Therefore, the resultant mixture has 50 cc of O2 + 50 cc of CO2