Gm mol. wt. of Cl2 = (35.5 × 2) = 71 g
Vol. occupied by 71 g of Cl2 = 22.4 lit [s.t.p.]
⇒ Vol. occupied by 53.5 g of Cl2 = 22.4\over 71 × 53.5 = 16.87 lit
Therefore, volume occupied by 53.5 g of Cl2 is 16.87 lit
Gm mol. wt. of Cl2 = (35.5 × 2) = 71 g
Vol. occupied by 71 g of Cl2 = 22.4 lit [s.t.p.]
⇒ Vol. occupied by 53.5 g of Cl2 = 22.4\over 71 × 53.5 = 16.87 lit
Therefore, volume occupied by 53.5 g of Cl2 is 16.87 lit
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