4NH3 | + | 5O2 | → | 2NO | 6H2O |
4 vol | : | 5 vol | 4 vol |
To calculate the volume of oxygen required :
NH3 | : | O2 |
4 | : | 5 |
100 | : | x |
⇒ x = 5\over 4 × 100 = 125 cm3
Hence, volume of oxygen required = 125 cm3
4NH3 | + | 5O2 | → | 2NO | 6H2O |
4 vol | : | 5 vol | 4 vol |
To calculate the volume of oxygen required :
NH3 | : | O2 |
4 | : | 5 |
100 | : | x |
⇒ x = 5\over 4 × 100 = 125 cm3
Hence, volume of oxygen required = 125 cm3
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