Question

Propane burns in air according to the following equation :
C3H8 + 5O2 ⟶ 3CO2 + 4H2O.
What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen.

August 2, 2024

Answer

Given, 20% of air contains oxygen

∴ 20% of 1000 cm³= $20\over 100$ × 1000 = 200 cm³

C₃H₈	+	5O₂	→	3CO₂	4H₂O
1 vol	:	5 vol		3 vol	4 vol

To calculate the volume of propane consumed :

O₂	:	C₃H₈
5	:	1
200	:	x

⇒ x = $1\over 5$ × 200 = 40 cm³

Hence, volume of propane is consumed is 40 cm³

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