Given, 20% of air contains oxygen
∴ 20% of 1000 cm3 = 20\over 100 × 1000 = 200 cm3
C3H8 | + | 5O2 | → | 3CO2 | 4H2O |
1 vol | : | 5 vol | 3 vol | 4 vol |
To calculate the volume of propane consumed :
O2 | : | C3H8 |
5 | : | 1 |
200 | : | x |
⇒ x = 1\over 5 × 200 = 40 cm3
Hence, volume of propane is consumed is 40 cm3