Calculate the mass of :
(i) 10^22 atoms of sulphur.
(ii) 0.1 mole of carbon dioxide.
[S = 32, C = 12 and O = 16 and Avogadro’s Number 6 × 10^23]

(i) gram molecular mass of S = 32

6 × 10²³ atoms weigh = 32 g

10²² atoms will weigh = 32\over6×10^23 × 10²²

= 0.533 g

(ii) 1 mole of carbon dioxide weighs = C + 2(O)

= 12 + 2(16)

= 12 + 32 = 44 g

∴ 0.1 mole of carbon dioxide weighs = 44 × 0.1 = 4.4 g.

Hence, mass of 10²² atoms of sulphur = 0.533 g.

and mass of 0.1 mole of carbon dioxide = 4.4 g.