gram molecular mass of SO2 = 32 + 2(16)
= 32 + 32 = 64 g
64 g of SO2 occupy 22.4 lit of vol.
320 g of SO2 will occupy = 22.4\over64 × 320 = 112 lit
Hence, volume of 320 g of SO2 = 112 lit.
gram molecular mass of SO2 = 32 + 2(16)
= 32 + 32 = 64 g
64 g of SO2 occupy 22.4 lit of vol.
320 g of SO2 will occupy = 22.4\over64 × 320 = 112 lit
Hence, volume of 320 g of SO2 = 112 lit.