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Question

Calculate the mass of Calcium that will contain the same number of atoms as are present in 3.2 gm of sulphur. [S = 32, Ca = 40]

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Answer

1 mole of Sulphur weighs 32 g and contains 6.02 × 1023 atoms

∴ 3.2 g of Sulphur will contain = 6.02 × 10^{23}\over32 × 3.2

= 6.02 × 1022 atoms.

6.02 × 1023 atoms of Ca weighs = 40 g

∴ 6.02 × 1022 atoms of Ca will weigh

= 40 \over6.02 × 10^{23} × 6.02 × 1022 = 4 g.

Hence, mass = 4 g.

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