Molecular weight of urea [CO(NH2)2]
= 12 + 16 + 2[14 + 2(1)]
= 12 + 16 + 2[16]
= 28 + 32
= 60 g
Converting the given weight of urea in grams,
1000 kg of urea = 1000 × 103 g of urea
60 g of urea contains 28 g of nitrogen
∴ 1000 × 103 g of urea will contain = 28\over 60 × 1000 × 1000
= 466.66 x 103 g ≈ 467 × 103 g
= 467 kg of nitrogen.
Hence, mass of nitrogen is 467 kg