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Question

Calculate the percentage of platinum in ammonium chloroplatinate (NH4)2 PtCl6
(Give your answer correct to the nearest whole number.
[N = 14, H = 1, Cl = 35.5, Pt = 195]

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Answer

Molecular weight of ammonium chloroplatinate (NH4)2PtCl6

= 2{14 + 4(1)} + 195 + 6(35.5)

= 2(18) + 195 + 213

= 444 g

444 g of ammonium chloroplatinate contains 195 g of Pt

∴ 100 g of ammonium chloroplatinate will contain

= 195\over444 × 100

= 43.91% = 44%

Hence, 44% percentage of platinum is present in ammonium chloroplatinate

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