Molecular weight of sodium aluminium fluoride (Na3AlF6)
= 3(23) + 27 + 6(19)
= 69 + 27 + 114
= 210 g
210 g of sodium aluminium fluoride contains 69 g of Na
∴ 100 g of sodium aluminium fluoride will contain
= 69\over 210 × 100
= 32.85% = 33%
Hence, percentage of sodium in sodium aluminium fluoride (Na3AlF6) is 33%