Element | % composition | At. wt. | Relative no. of atoms | Simplest ratio |
---|---|---|---|---|
Carbon | 82.76 | 12 | 82.76/12 = 6.89 | 6.89/6.89 = 1 × 2 = 2 |
Hydrogen | 17.24 | 1 | 17.24/1 = 17.24 | 17.24/6.89 = 2.5 × 2 = 5 |
Simplest ratio of whole numbers = C : H = 1 : 2.5 = 2 : 5
Hence, the empirical formula is C2H5
Empirical formula weight = 2(12) + 5(1) = 29
V.D. = 29
Molecular weight = 2 × V.D. = 2 × 29 = 58
n = Molecular\ weight\over Empirical\ formula\ weight
= 58\over 29 = 2
∴ Molecular formula = (C2H5)2 = C4H10