Na2CO3.10H2O | → | Na2CO3 | + | 10H2O |
286 g | 106 g | 180 g |
286 g of washing soda had 106 g of anhydrous sodium carbonate
∴ 57.2 g will have = 106\over286 × 57.2 = 21.2 g anhydrous sodium carbonate.
Hence, 21.2 g anhydrous sodium carbonate is left.
Na2CO3.10H2O | → | Na2CO3 | + | 10H2O |
286 g | 106 g | 180 g |
286 g of washing soda had 106 g of anhydrous sodium carbonate
∴ 57.2 g will have = 106\over286 × 57.2 = 21.2 g anhydrous sodium carbonate.
Hence, 21.2 g anhydrous sodium carbonate is left.