233 g of BaSO4 is obtained from 142 g of Na2SO4
6.99 g of BaSO4 will be obtained from 142\over233 × 6.99 = 4.26 g of Na2SO4.
∴ In 10 g mixture 4.26\over10 × 100 = 42.6% Na2SO4 is present.
Hence, 42.6% Na2SO4 is present in the original mixture
233 g of BaSO4 is obtained from 142 g of Na2SO4
6.99 g of BaSO4 will be obtained from 142\over233 × 6.99 = 4.26 g of Na2SO4.
∴ In 10 g mixture 4.26\over10 × 100 = 42.6% Na2SO4 is present.
Hence, 42.6% Na2SO4 is present in the original mixture