(a) (i) A cricket/hockey ball which has been hit hard and is travelling fast.
(ii) A shot put thrown by an athlete
(b) Let the body of mass m at height h above the ground starting from rest, be falling freely.
Total energy of the body at height h
= mgh (PE) + 0 (KE) = mgh
After the body has fallen freely through a distance x (say),
KE = mgh, PE = mg (h โ x)
Total energy = KE + PE
= mgh + mg (h โ x) = mgh
When it reaches the ground KE ={1\over2} m.2gh = mgh
PE = 0, Total Energy = KE + PE = mgh
Thus, the total mechanical energy, which is the sum of KE and PE is always equal to mgh.