Linear momentum of first object, π1 = π1π£1 and of second object, π2= π2π£2
But, π1 = π2
or,Β Β π1π£1 = π2π£2
If π1 < π2 then π£1 > π£2
(K.E.)1 = {1\over2}(π1π£1)π£1 = {1\over2}π1π£1
and (K.E.)2 = {1\over2}(π2π£2)π£2 = {1\over2}π2π£2
So, {({K.E.})_1}\over{({K.E.})_2} = {{1\over2}p_1v_1}\over{{1\over2}p_2v_2} = {v_1\over v_2}
But, π£1 > π£2
Therefore, (K.E.)1 > (K.E.)2