Linear momentum of first object, ๐1 = ๐1๐ฃ1 and of second object, ๐2= ๐2๐ฃ2
But, ๐1 = ๐2
or,ย ย ๐1๐ฃ1 = ๐2๐ฃ2
If ๐1 < ๐2 then ๐ฃ1 > ๐ฃ2
(K.E.)1 = {1\over2}(๐1๐ฃ1)๐ฃ1 = {1\over2}๐1๐ฃ1
and (K.E.)2 = {1\over2}(๐2๐ฃ2)๐ฃ2 = {1\over2}๐2๐ฃ2
So, {({K.E.})_1}\over{({K.E.})_2} = {{1\over2}p_1v_1}\over{{1\over2}p_2v_2} = {v_1\over v_2}
But, ๐ฃ1 > ๐ฃ2
Therefore, (K.E.)1 > (K.E.)2