Linear momentum of first object, 𝑝1 = 𝑚1𝑣1 and of second object, 𝑝2= 𝑚2𝑣2
But, 𝑝1 = 𝑝2
or, 𝑚1𝑣1 = 𝑚2𝑣2
If 𝑚1 < 𝑚2 then 𝑣1 > 𝑣2
(K.E.)1 = {1\over2}(𝑚1𝑣1)𝑣1 = {1\over2}𝑝1𝑣1
and (K.E.)2 = {1\over2}(𝑚2𝑣2)𝑣2 = {1\over2}𝑝2𝑣2
So, {({K.E.})_1}\over{({K.E.})_2} = {{1\over2}p_1v_1}\over{{1\over2}p_2v_2} = {v_1\over v_2}
But, 𝑣1 > 𝑣2
Therefore, (K.E.)1 > (K.E.)2