First, calculate the equivalent resistance of the two resistors in parallel (6 Ω and 3 Ω):

The formula for parallel resistors is:

1/R_parallel = 1\over \text{R}_1 + 1\over \text{R}_2

Substituting the values:

1/R_parallel = 1\over6 + 1\over3

1/R_parallel = 1\over6 + 2\over6 = 3/6

R_parallel = 6\over3 = 2 Ω

Now, add the series resistor (1 Ω) to the equivalent resistance of the parallel resistors:

R_total = R_parallel + R_Series

R_total = 2 Ω + 1 Ω = 3 Ω

So, the total equivalent resistance is 3 Ω.