What would be the equivalent resistance of a circuit containing resistances of 6 Ω and 3 Ω connected in parallel with another resistance of 1 Ω connected in series?
WBBSE
Class X
Physical Science
Current Electricity
01 Mark
2024
First, calculate the equivalent resistance of the two resistors in parallel (6 Ω and 3 Ω):
The formula for parallel resistors is:
1/Rparallel = 1\over \text{R}_1 + 1\over \text{R}_2
Substituting the values:
1/Rparallel = 1\over6 + 1\over3
1/Rparallel = 1\over6 + 2\over6 = 3/6
Rparallel = 6\over3 = 2 Ω
Now, add the series resistor (1 Ω) to the equivalent resistance of the parallel resistors:
Rtotal = Rparallel + RSeries
Rtotal = 2 Ω + 1 Ω = 3 Ω
So, the total equivalent resistance is 3 Ω.
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