Skip to content
WBBSEClass 10MathematicsRight Circular Cone02 Mark2022 Easy

QQuestion

Find the total surface area of a cone whose diameter of the base is 20 cm and slant height is 25 cm.

Exam-ready answer • 02 Mark

Answer

Diameter = 20 cm ⇒ radius (r) = 10 cm

Slant height (l) = 25 cm

Total Surface Area (TSA) of cone = πrl + πr²

= π × 10 × 25 + π × 10²

= 250π + 100π

= 350π cm²

TSA = 350 × \frac{22}{7} = 1100 cm²

Was this answer helpful?

Related Questions

More WBBSE Easy level questions

1/12

State True or False: The height, radius, and slant height of a right circular cone are always the three sides of a right-angled triangle.

Easy 01 Mark

If the volume of a right circular cone is V cubic unit, the base area is A sq. unit and the height is H unit, then find the value of

Easy 02 Mark

If x be the volume, y be the area of the base and z be the height of a cone then the value of x / yz is 3.

Easy 01 Mark

If V be the volume, R be the radius of the base and H be the height of a right circular cone, then H = ____

Easy 01 Mark

If V be the volume, R be the radius of the base and H be the height of a right circular cone, then H = ____.

Easy 01 Mark

In a right circular conical tent, 11 persons can stay. For each person, 4 sq. m space in the base and 20 cu.m. air are necessary. Determine the height of the tent put up exactly for 11 persons.

Moderate 04 Mark

Curved surface area of a right circular cone is 154√2 sq cm and radius of the base 7 cm. Find its vertical angle.

Moderate 04 Mark

The height of a right circular cone is twice the radius of the base. If the height were seven times the diameter of the base then the volume of the cone would have been 539 cu cm more. Find the height of the cone.

Moderate 04 Mark

Asha buys ₹ 20 shares of a company which pays 9% dividend at such a price that she gets a return of 12% on her investment. At what price did she buy each share? (a) ₹ 20 (b) ₹ 15 (c) ₹ 25 (d) ₹ 18

Easy

The fourth term of a Geometric Progression (G.P.) is 16 and its seventh term is 128. Find its: (a) common ratio (b) first term

Easy 03 Mark

If A = , then A² is equal to: (a) (b) (c) (d)

Easy 01 Mark

Statement 1: The point which is equidistant from three non-collinear points D, E and F is the circumcentre of △DEF. Statement 2: The incentre of a triangle is the point where the bisectors of the angles intersect. (a) Both statements are true. (b) Both statements are false. (c) Statement 1 is true and Statement 2 is false. (d) Statement 1 is false and Statement 2 is true.

Easy 01 Mark