1
\mathrm{f}=\frac{1}{\mathrm{T}}
2
\mathrm{v}=\mathrm{f}\mathrm{\lambda}
3
\text{Depth}=\frac{\mathrm{v}\mathrm{t}}{2}
4
\mathrm{h}=\frac{\mathrm{t}}{2}\sqrt{\mathrm{V}^{2}-\mathrm{v}^{2}}
5
\mathrm{T}=\frac{1}{\mathrm{f}}
FORMULA CHAPTER
Chapter 07 – Sound
ICSEClass 10Physics5 formulas
Revise ICSE Class 10 Chapter 07 Sound formulas for frequency, time period, wavelength, wave speed and echo calculations.
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Frequency from Time Period
\mathrm{f}=\frac{1}{\mathrm{T}}
SymbolMeaningUnit
fFrequencyHz
TTime periods
Worked example
Given: T = 0.25 s Calculation: f = 1/0.25 Answer: f = 4 Hz
Wave Equation
\mathrm{v}=\mathrm{f}\mathrm{\lambda}
Worked example
Given: f = 500 Hz, wavelength = 0.68 m Calculation: v = 500 × 0.68 Answer: v = 340 m/s
Echo Depth Formula
\text{Depth}=\frac{\mathrm{v}\mathrm{t}}{2}
SymbolMeaningUnit
vSpeed of soundm/s
tEcho times
Worked example
Given: v = 1500 m/s, t = 2 s Calculation: Depth = 1500 × 2 / 2 Answer: Depth = 1500 m
Height of a Moving Aeroplane from Echo
\mathrm{h}=\frac{\mathrm{t}}{2}\sqrt{\mathrm{V}^{2}-\mathrm{v}^{2}}
SymbolMeaningUnit
hHeight of aeroplanem
tTime differences
VSpeed of sound in airm/s
vSpeed of aeroplanem/s
Worked example
Given: V = 340 m/s, v = 100 m/s, t = 2 s Calculation: h = 1 × √(340² − 100²) Answer: h ≈ 325 m
Time Period from Frequency
\mathrm{T}=\frac{1}{\mathrm{f}}
SymbolMeaningUnit
TTime periods
fFrequencyHz
Worked example
Given: f = 5 Hz Calculation: T = 1/5 Answer: T = 0.2 s