Publisher | : Oriental Book Company Private Limited |
Material | : Madhyamik Physical Science Solution |
Subject | : Physical Science |
Class | : 9 (Madhyamik) |
Chapter Name | : Mole Concept |
In-Text Questions
Question 4.2.1
What do you mean by atomic mass of chlorine is 35.46 ?
Answer
This means 35.46 = (Average mass of an atom of Cl in natural isotopic mixture / Mass of an atom of C¹²) × 12
Question 4.2.2
The atomic weight of oxygen is 15.994 u. What is the weight of one atom of oxygen in gram?
Answer
We know, 1 amu = 1.6603 × 10⁻²⁴ g
Weight of one atom of oxygen = Atomic mass × 1 amu
= 15.994 × 1.6603 × 10⁻²⁴ g
= 2.656 × 10⁻²³ g
Question 4.2.3
What do you mean by atomic mass unit ?
Answer
One atomic mass unit (amu or u) is defined as 1/12th of the mass of one atom of C¹² isotope.
1 amu = (Mass of one atom of C¹²) / 12
In grams, 1 amu = 1.6603 × 10⁻²⁴ g.
Question 4.2.4
What do you mean by molecular mass of ammonia is 17 ?
Answer
The molecular mass of ammonia (NH₃) is 17 u, which means that one molecule of ammonia is 17 times heavier than 1/12th of the mass of one C¹² atom.
Question 4.2.5
What do you mean by one gram atom of oxygen ?
Answer
One gram atom of oxygen is 16 g, which means the atomic mass of oxygen is 16 u, and when expressed in grams, it is called one gram atom of oxygen
One gram atom of oxygen is 16 g. Oxygen, its atomic mass is 16.
Question 4.2.6
How many gram molecules of ammonia are present in 100 grams of ammonia ?
Answer
No. of moles = \text{given mass} \over \text{molar mass}
For ammonia, molar mass = 17 g/mol
No. of moles = 100 \over 17
= 5.88 moles
So, 100 g of ammonia contains 5.88 gram-molecules of ammonia.
Question 4.2.7
Define Avogadro’s number, mention its value.
Answer
Avogadro’s number is defined as the number of particles (atoms, molecules, or ions) present in one mole of a substance.
Its value is 6.022 × 10²³ particles per mole.
Question 4.2.8
What is the volume of 4 gms of hydrogen at STP ?
Answer
At STP, 1 mole of hydrogen gas (H₂) = 2 g occupies 22.4 L.
No. of moles in 4 g of H₂ = 4 g / 2 g = 2 moles
Volume = 2 × 22.4 L = 44.8 L
Thus, 4 g of hydrogen occupies 44.8 L at STP.
Question 4.2.9
How much volume will be occupied by 1.5 gram-molecules of oxygen ?
Answer
At STP, 1 gram-molecule (1 mole) of O₂ occupies 22.4 L.
Volume of 1.5 gram-molecules of O₂ = 1.5 × 22.4 L
= 33.6 L
Thus, 1.5 gram-molecules of oxygen occupy 33.6 L at STP.
Very short answer type questions :
Choose the correct answer :
Question 1 (i)
‘Mole’ means—
(a) a molecule
(b) number of molecules
(c) number of atoms
(d) Avogadro’s number of any particle.
Answer
(d) Avogadro’s number of any particle.
Explanation:
A mole represents 6.022 × 10²³ particles (atoms, molecules, or ions) of a substance, which is known as Avogadro’s number. It is a fixed quantity that helps in calculations related to atoms and molecules.
Question 1 (ii)
0.012 kg. of C-12 isotope contains how many C-12 atoms ?
(a) 12 g
(b) 6.022 × 10²³
(c) 1.66 × 10⁻²⁴ g
(d) 12g. atom.
Answer
(b) 6.022 × 10²³
Explanation:
0.012 kg = 12 g of C-12 isotope is defined as 1 mole of C-12 atoms.
Since 1 mole = Avogadro’s number = 6.022 × 10²³ atoms, 12 g of C-12 contains 6.022 × 10²³ atoms.
Question 1 (iii)
Avogadro’s number is used in—
(a) chemistry only
(b) physics only
(c) Biology only
(d) chemistry, physics and biology
Answer
(d) chemistry, physics, and biology
Explanation:
Avogadro’s number is used in:
- Chemistry (for mole concept, atomic and molecular calculations)
- Physics (for gas laws and calculations related to atomic theory)
- Biology (for understanding molecular biology and counting molecules like DNA, proteins, etc.)
Question 1 (iv)
Unit of relative atomic mass is—
(a) gram
(b) kilogram
(c) amu
(d) no unit
Answer
(d) no unit
Explanation:
Relative atomic mass is a ratio of the mass of an atom to 1/12th of the mass of a C-12 atom. Since it is a ratio, it has no unit.
Answer the following questions
Question 2 (i)
What is the value of Avogadro’s number ?
Answer
6.022 × 10²³
Question 2 (ii)
One atomic mass unit (amu) is how much in grams ?
Answer
1 amu = 1.6603 × 10⁻²⁴ g
Question 2 (iii)
What is the volume of 7 g nitrogen at STP ?
Answer
5.6 L
Explanation:
Molecular mass of N₂ = 2 × 14 = 28 g
1 mole (28 g) of N₂ gas occupies 22.4 L at STP
Volume of 7 g of N₂ = (22.4 / 28) × 7 = 5.6 L
Fill up the blanks
Question 3 (i)
Volume of one mole of oxygen at 50°C and 760 mm pressure is higher than ___ litres.
Answer
22.4 litres
Explanation:
At STP (0°C, 1 atm pressure), 1 mole of oxygen occupies 22.4 L. At higher temperatures, the volume increases due to gas expansion.
Question 3 (ii)
8 g oxygen is equal to ___ moles of oxygen.
Answer
0.25 moles
Explanation:
Molar mass of O₂ = 32 g
No. of moles = 8 g / 32 g = 0.25 moles
Question 3 (iii)
Atomic mass of element × 1 amu = ___ mass of one atom of element.
Answer
Since 1 amu = 1.6603 × 10⁻²⁴ g, multiplying atomic mass with 1 amu gives the actual mass of an atom in grams.
Supply the missing word from these in brackets
Question 4 (i)
The mass of one mole molecules of any substance is equal to ___ (gram molecular mass/mass of one molecule)
Answer
gram molecular mass
Explanation:
1 mole of a substance contains Avogadro’s number of molecules, so its mass is equal to the gram molecular mass.
Question 4 (ii)
12U of carbon contains ___ (only 1 atom of carbon/12g of carbon)
Answer
only 1 atom of carbon
Explanation:
12U (atomic mass unit) refers to the mass of a single carbon atom, not grams of carbon.
Question 4 (iii)
1 mole of carbon contains ___ (12gC/12U of carbon)
Answer
12g of C
Explanation:
Since 1 mole of carbon contains Avogadro’s number of atoms (6.022 × 10²³ atoms), its mass is 12 g
Indicate which of the following statements are true and which are false
Question 5 (i)
IUPAC accepted H=1 isotope as standard substance to determine the atomic mass of other elements.
Answer
False
Explanation:
IUPAC has accepted C-12 isotope as the standard for atomic mass measurement, not hydrogen.
Question 5 (ii)
One gram molecule of water contains two moles of hydrogen atom.
Answer
True
Explanation:
- 1 gram-molecule (1 mole) of H₂O contains 1 mole of H₂O molecules.
- Each H₂O molecule has 2 hydrogen atoms, so 1 mole of H₂O contains 2 moles of hydrogen atoms.
Question 5 (iii)
Mass of gram atom of nitrogen is 28g.
Answer
False
Explanation:
A gram atom of nitrogen (N) is 14 g (since atomic mass of nitrogen is 14 u).
But 1 mole of N₂ molecules (gas) is 28 g. The statement is incorrect because it confuses atomic nitrogen (N) with molecular nitrogen (N₂).
Short answer type questions
Question 1
What do you mean by the term mole ? Give one example to show the enormity of Avogadro’s number.
Answer
A mole is the amount of substance that contains 6.022 × 10²³ elementary particles (atoms, molecules, or ions). It is a fundamental unit in chemistry for counting large numbers of particles.
Example:
If we take 1 mole of sand grains, the number of grains would be 6.022 × 10²³, which is so vast that it could cover the entire Earth with a thick layer of sand.
Question 2
What do you mean by atomic mass unit ?
Answer
Atomic Mass Unit (amu or u) is defined as 1/12th of the mass of one atom of carbon-12 (C¹²) isotope.
Question 3
Define molecular mass taking C-12 isotope as the standard substance.
Answer
Molecular mass is the sum of the atomic masses of all the atoms present in a molecule, measured relative to 1/12th of the mass of a C¹² atom.
Question 4
Formula mass is taken for chemical calculation for which compounds ?
Answer
Formula mass is used for ionic compounds that do not exist as discrete molecules but as a lattice of ions.
Examples:
- NaCl (Sodium chloride) → Formula mass = (23 + 35.5) = 58.5 u
- MgCl₂ (Magnesium chloride) → Formula mass = (24 + 2 × 35.5) = 95 u
Question 5
What is molar volume ? What is the value of their volume ?
Answer
Molar volume is the volume occupied by 1 mole of a gas at standard temperature and pressure (STP).
At STP (0°C and 1 atm pressure), molar volume = 22.4 L.
This means 1 mole of any gas occupies 22.4 L at STP.
Question 6
What is the number of molecules of sulphur (S₈) present in 24 g of solid sulphur.
Answer
Molar mass of S₈ = 8 × 32 = 256 g
Number of moles in 24 g of S₈ = \frac{24} {256}
= 0.09375 moles
Number of molecules = moles × Avogadro’s number
= 0.09375 × 6.022 × 10²³
= 5.64 × 10²² molecules of S₈
Long answer type questions
Question 1
Define atomic mass of an element taking C¹² as standard. What is gram molecular volume ? What is the mass of one mole of CO₂ ? (2+2+1)
Answer
Atomic mass is the mass of an atom of an element relative to 1/12th of the mass of a C¹² atom. It is a dimensionless number.
Gram molecular volume is the volume occupied by one mole of any gas at STP, which is 22.4 L.
Mass of one mole of CO2:
Molecular mass of CO2 = (1 × 12) + (2 × 16) = 44 g
So, mass of 1 mole of CO2 = 44 g
Question 2
(a) What is mole ? What is relation with Avogadro’s number.
(b) To show the vastness of mole, cite one example.
Answer
(a) A mole is a unit used to measure the amount of substance containing Avogadro’s number of particles (6.022 × 10²³ particles).
Mathematically,
1 mole = 6.022 × 10²³ atoms/molecules/ions
(b) If we take 1 mole of marbles, they would cover the entire surface of the Earth with a thick layer, showing how large 6.022 × 10²³ is.
Question 3
(a) Why temperature and pressure are to mention to give the value of molar volume of gaseous substance ?
(b) What is the volume of one millimole of CO2 at STP ? [Ans. 0.0224L]
Answer
(a) The volume of gases depends on temperature and pressure. At different conditions, gas expands or compresses. So, for consistency, molar volume is measured at standard temperature and pressure (STP), which is 0°C and 1 atm.
(b) At STP, 1 mole of any gas occupies 22.4 L.
1 millimole = 1/1000 moles = 10⁻³ moles
Volume at STP = 10⁻³ × 22.4 L = 0.0224 L
4. Match the quantities given in left hand column with their values in the right hand match
L.H Column | R.H Column |
---|---|
1. Avogadro’s number | (a) 3.011 × 10²³ molecule |
2. Molar volume of gas at STP | (b) 1.5 moles of C-atoms |
3. Mass of 4 moles of CO2 | (c) 2.007 × 10²³ atoms |
4. 9g. of H2O | (d) 6.022 × 10²³ particles |
5. 18 g of Carbon | (e) 176 g |
6. 9 g of aluminium | (f) 22.4 L |
Answer
L.H Column | R.H Column |
---|---|
1. Avogadro’s number | (d) 6.022 × 10²³ particles |
2. Molar volume of gas at STP | (f) 22.4 L |
3. Mass of 4 moles of CO2 | (e) 176 g |
4. 9g. of H2O | (a) 3.011 × 10²³ molecule |
5. 18 g of Carbon | (b) 1.5 moles of C-atoms |
6. 9 g of aluminium | (c) 2.007 × 10²³ atoms |