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Chapter 04 – Co-ordinate Geometry – Distance Formula | Class 9 Flash Formula

Formula

Master the Class 9 Madhyamik Mathematics Coordinate Geometry Formulas including Distance Formula, Equidistant Point, Collinearity of Points, and coordinate-based proofs of Isosceles Triangle, Equilateral Triangle, Right-Angled Triangle, Square, Rectangle, Rhombus, Parallelogram, and Kite. Each concept is explained with step-by-step solved examples for quick learning and exam preparation.

Distance Formula

Let A(x₁, y₁) and B(x₂, y₂) be the two points.

AB = √[(x₂ − x₁)² + (y₂ − y₁)²]

Example: Find the distance between the points A(2, 3) and B(8, 11). Using the formula, AB = √[(x₂ − x₁)² + (y₂ − y₁)²] = √[(8 − 2)² + (11 − 3)²] = √[6² + 8²] = √[36 + 64] = √100 = 10 units

Equidistant Point Formula

If a point P(x, y) is equidistant from two points A(x₁, y₁) and B(x₂, y₂), then

PA = PB

i.e.

√[(x − x₁)² + (y − y₁)²] = √[(x − x₂)² + (y − y₂)²]

After squaring both sides,

(x − x₁)² + (y − y₁)² = (x − x₂)² + (y − y₂)²

If P(x, 4) is equidistant from A(1, 2) and B(5, 6), find the value of x. Since P is equidistant from A and B, PA = PB √[(x − 1)² + (4 − 2)²] = √[(x − 5)² + (4 − 6)²] Squaring both sides, (x − 1)² + 4 = (x − 5)² + 4 (x − 1)² = (x − 5)² x² − 2x + 1 = x² − 10x + 25 8x = 24 x = 3 Therefore, P = (3, 4).

Condition of Collinearity

Three points A(x₁, y₁), B(x₂, y₂) and C(x₃, y₃) are collinear if

Distance AB + Distance BC = Distance AC

Example (Using Distance Formula) Check whether the points A(1, 2), B(3, 4) and C(5, 6) are collinear. Distance AB: AB = √[(3 − 1)² + (4 − 2)²] = 2√2 Distance BC: BC = √[(5 − 3)² + (6 − 4)²] = 2√2 Distance AC: AC = √[(5 − 1)² + (6 − 2)²] = 4√2 Now, AB + BC = 2√2 + 2√2 = 4√2 = AC Therefore, AB + BC = AC

Condition for Isosceles Triangle

A triangle is isosceles if any two sides are equal.

AB = AC or AB = BC or AC = BC

Example Let A(0, 0), B(4, 0) and C(2, 3) AB = √[(4 − 0)² + (0 − 0)²] = 4 AC = √[(2 − 0)² + (3 − 0)²] = √13 BC = √[(2 − 4)² + (3 − 0)²] = √13 Since AC = BC, ΔABC is an Isosceles Triangle.

Condition for Right-Angled Triangle

A triangle is right-angled if

AB² + BC² = AC² (where AC is the longest side)

Example Let A(0, 0), B(3, 0) and C(3, 4) AB = 3, BC = 4 and AC = 5 AB² + BC² = 3² + 4² = 25 AC² = 5² = 25 Since AB² + BC² = AC², ΔABC is a Right-Angled Triangle.

Condition for Equilateral Triangle

A triangle is equilateral if

Length of AB = Length of BC = Length of AC

Example Let A(0, 0), B(2, 0) and C(1, √3) AB = √[(2 − 0)² + (0 − 0)²] = 2 AC = √[(1 − 0)² + (√3 − 0)²] = 2 BC = √[(1 − 2)² + (√3 − 0)²] = 2 Since AB = BC = AC = 2, ΔABC is an Equilateral Triangle.

Condition for Square

A quadrilateral is a Sqaure if

Sides : Length of AB = Length of BC = Length of CD = Length of DA and

Diagonals: Length of AC = Length of BD

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