\mathrm{f}=\frac{1}{\mathrm{T}}
\mathrm{v}=\mathrm{f}\mathrm{\lambda}
\text{Depth}=\frac{\mathrm{v}\mathrm{t}}{2}
\mathrm{h}=\frac{\mathrm{t}}{2}\sqrt{\mathrm{V}^{2}-\mathrm{v}^{2}}
\mathrm{T}=\frac{1}{\mathrm{f}}
FORMULA CHAPTER
\mathrm{f}=\frac{1}{\mathrm{T}}
\mathrm{v}=\mathrm{f}\mathrm{\lambda}
\text{Depth}=\frac{\mathrm{v}\mathrm{t}}{2}
\mathrm{h}=\frac{\mathrm{t}}{2}\sqrt{\mathrm{V}^{2}-\mathrm{v}^{2}}
\mathrm{T}=\frac{1}{\mathrm{f}}
\mathrm{f}=\frac{1}{\mathrm{T}}
Question: A wave has a time period of 0.25 s. Find its frequency.
Calculation: f = 1/T
⇒ f = 1/0.25
⇒ f = 4 Hz
Answer: The frequency is 4 Hz.
\mathrm{v}=\mathrm{f}\mathrm{\lambda}
Question: Using Wave Equation, solve the case where f = 500 Hz, wavelength = 0.68 m.
Calculation: Apply the Wave Equation formula.
Step 1: Substitute the stated values into the formula.
Step 2: v = 500 × 0.68.
Answer: v = 340 m/s.
\text{Depth}=\frac{\mathrm{v}\mathrm{t}}{2}
Question: Using Echo Depth Formula, solve the case where v = 1500 m/s, t = 2 s.
Calculation: Apply the Echo Depth Formula formula.
Step 1: Substitute the stated values into the formula.
Step 2: Depth = 1500 × 2 / 2.
Answer: Depth = 1500 m.
\mathrm{h}=\frac{\mathrm{t}}{2}\sqrt{\mathrm{V}^{2}-\mathrm{v}^{2}}
Question: Using Height of a Moving Aeroplane from Echo, solve the case where v = 340 m/s, v = 100 m/s, t = 2 s.
Calculation: Apply the Height of a Moving Aeroplane from Echo formula.
Step 1: Substitute the stated values into the formula.
Step 2: h = 1 × √(340² − 100²).
Answer: h ≈ 325 m.
\mathrm{T}=\frac{1}{\mathrm{f}}
Question: Using Time Period from Frequency, solve the case where f = 5 Hz.
Calculation: Apply the Time Period from Frequency formula.
Step 1: Substitute the stated values into the formula.
Step 2: T = 1/5.
Answer: T = 0.2 s.