Madhyamik Class 10 Physical Science Question Paper Solved 2024
Physical Science
Time – Three Hours Fifteen Minutes
(First fifteen minutes for reading the Question paper only)
Full Marks – 90
(For Regular and Sightless Regular Candidates)
Full Marks – 100
(For External and sightless External Candidates)
Special credits will be given for answers which are brief and to the point.
Marks will be deducted for spelling mistakes, untidiness and bad handwriting.
Figures in the margin indicate full marks for each Question.
Only the External Candidates will answer Group -E
Figures in the margin indicate full marks for each Question.
Group – A
Multiple choice questions. Four alternative answers are given below each of the following questions. Write the correct one: [1 × 15 = 15]
Question 1.1
The major constituent of Biogas is
(a) CH4
(b) CFC
(c) CO2
(d) CO
Solution
(a) CH4
Explanation
Biogas primarily consists of methane (CH4), with small amounts of other gases like carbon dioxide (CO2). Methane is the main combustible component.
Question 1.2
A real gas behaves as an ideal gas at
(a) High pressure and high temperature
(b) High pressure and low temperature
(c) Low pressure and high temperature
(d) Low pressure and low temperature
Solution
(c) Low pressure and high temperature
Explanation
At low pressure and high temperature, intermolecular forces become negligible, and gas molecules move more freely, making a real gas behave like an ideal gas.
Question 1.3
The number of moles present in 44.8 litres CO2 at STP is
(a) 3 (b) 1 (c) 2 (d) 1.5
Solution
(c) 2
Explanation
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. Therefore, 44.8 liters of CO₂ corresponds to 2 moles (44.8 / 22.4 = 2).
Question 1.4
The value of the ratio of the volume coefficient to the pressure coefficient of an ideal gas is
(a) 1/2
(b) 0
(c) 1/273
(d) 1
Solution
(d) 1
Explanation
For an ideal gas, the ratio of the volume coefficient to the pressure coefficient is 1, as they are directly proportional and follow the ideal gas law.
Question 1.5
The equation expressing the correlation between refractive index and wavelength of light is
(a) μ = A + B/λ
(b) μ = A + Bλ²
(c) μ = Aλ + B
(d) μ = A + B/λ²
Solution
(d) μ = A + B/λ²
Explanation
The refractive index (μ) of light is inversely proportional to the square of the wavelength (λ). This is represented by the equation μ = A + B/λ².
Question 1.6
The magnified virtual image is formed by
(a) convex mirror
(b) convex lens
(c) plane mirror
(d) concave lens
Solution
(d) concave lens
Explanation
A concave lens forms a magnified virtual image when the object is placed between the lens and the focus.
Question 1.7
An electric current is flowing through a wire. If in this situation the wire is stretched to increase its length then the flow of current through the wire
(a) will increase
(b) will decrease
(c) will at first increase and then decrease
(d) will not depend upon the increase in the length of the wire
Solution
(b) will decrease
Explanation
Stretching the wire increases its resistance, which decreases the current for a constant voltage, according to Ohm’s law (I = V/R).
Question 1.8
If 5 ampere current is conducted for 30 seconds through any conductor then the total conducted charge would be
(a) 6 coulomb
(b) 150 coulomb
(c) 300 coulomb
(d) 30 coulomb
Solution
(b) 150 coulomb
Explanation
The total charge (Q) is given by
Q = I × t,
where I is current (5 A) and
t is time (30 seconds).
So, Q = 5 × 30 = 150 coulombs.
Question 1.9
The number of a and β particles emitted in the reaction 86A222 → 84B210 wouldrespectively be
(a) 6α, 3β
(b) 3α, 4β
(c) 4α, 3β
(d) 3α, 6β
Solution
(b) 3α, 4β
Question 1.10
If the elements are arranged in ascending order of their electropositivity, then choose the correct order
(a) C < N < 0 < F
(b) C > N > 0 > F
(c) O < N < C < F
(d) F > C > O > N
Solution
(b) C > N > 0 > F
Explanation
Electropositivity decreases from left to right across a period. Therefore, carbon (C) is more electropositive than nitrogen (N), oxygen (O), and fluorine (F).
Question 1.11
The electronic configuration of Na and Cl atoms in the compound NaCl is
(a) Na – 2, 8, 8 : Cl – 2, 8
(b) Na – 2, 8, 7 : Cl – 2, 8, 1
(c) Na – 2, 8, 1 : Cl – 2, 8, 7
(d) Na – 2, 8, : Cl – 2, 8, 8
Solution
(c) Na – 2, 8, 1 : Cl – 2, 8, 7
Explanation
Sodium (Na) has an electron configuration of 2, 8, 1, and chlorine (Cl) has an electron configuration of 2, 8, 7. In NaCl, Na loses one electron and Cl gains one electron to form a stable ionic bond.
Question 1.12
Decide which of the following statements is not correct regarding the conductance of electricity through electrolyte
(a) Chemical change occurs
(b) Conducts electricity in dissolved or molten state
(c) Resistance usually increases with the increase in temperature
(d) Electricity is conducted through ions
Solution
(c) Resistance usually increases with the increase in temperature
Explanation
This statement is incorrect. In electrolytes, conductivity generally increases with temperature due to higher ion mobility, while resistance decreases.
Question 1.13
The gas which is identified by using Nessler’s reagent is
(a) NO2
(b) H₂S
(c) HCl
(d) NH3
Solution
(d) NH₃
Explanation
Nessler’s reagent is used to detect ammonia (NH₃) gas. It forms a yellow-brown color when ammonia is present.
Question 1.14
The metal which is extracted through thermal reduction is
(a) Ag
(b) Mg
(c) Fe
(d) Au
Solution
(c) Fe
Explanation
Iron (Fe) is extracted by thermal reduction (reduction of iron ore with carbon) in a blast furnace.
Question 1.15
Identify the chemical reaction which yields chloroform
(a) CH4 + Cl2
(b) CH3Cl + Cl2
(c) CH2Cl2 + Cl2
(d) CHCl3 + Cl2
Solution
(c) CH2Cl2 + Cl2
Explanation
Chloroform (CHCl₃) is produced by the chlorination of dichloromethane (CH₂Cl₂) in the presence of chlorine gas.
Group – B
2. Answer the following questions(alternatives are to be noted):
Question 2.1
Chlorine atom (Cl) destroys Ozone molecule (O3) – show with the help of a chemical reaction. [1]
Solution
Chlorine reacts with ozone:
Cl + O3 → ClO + O2
Chlorine monoxide reacts with another ozone molecule:
ClO + O3 → Cl + 2O2
Question 2.2
In which layer of the atmosphere is the minimum temperature noted? [1]
OR
In which layer of the atmosphere does the orbit of the International Space Station lie ? [1]
Solution
The minimum temperature in the atmosphere is noted in the thermosphere.
The orbit of the International Space Station (ISS) lies in the thermosphere.
Question 2.3
What is the nature of P vs 1/V graph? [1]
Solution
The nature of the P vs 1/V graph is hyperbolic.
Question 2.4
Write down the correlation between absolute temperature and density of gas. [1]
Solution
Density (ρ) ∝ 1/Temperature (T), when pressure is constant.
Question 2.5
The coefficient of linear expansion of aluminium is 24×10-6 ºC-1. What would be its value in the SI unit? [1]
OR
From which law is the value of the volume expansion coefficient of gas obtained? [1]
Solution
The value of the volume expansion coefficient of a gas is obtained from Charles’s Law (also known as the law of volumes).
Question 2.6
State whether the refractive index of a medium would increase or decrease if the angle of incidence is increased. [1]
Solution
The refractive index of a medium is independent of the angle of incidence.
Question 2.7
Where is the image formed if the object is placed in between f and 2f of a convex lens ? [1]
Solution
beyond 2f
Question 2.8
What would be the equivalent resistance of a circuit containing resistances of 6 Ω and 3 Ω connected in parallel with another resistance of 1 Ω connected in series? [1]
Solution
First, calculate the equivalent resistance of the two resistors in parallel (6 Ω and 3 Ω):
The formula for parallel resistors is:
1/Rparallel = 1\over \text{R}_1 + 1\over \text{R}_2
Substituting the values:
1/Rparallel = 1\over6 + 1\over3
1/Rparallel = 1\over6 + 2\over6 = 3/6
Rparallel = 6\over3 = 2 Ω
Now, add the series resistor (1 Ω) to the equivalent resistance of the parallel resistors:
Rtotal = Rparallel + RSeries
Rtotal = 2 Ω + 1 Ω = 3 Ω
So, the total equivalent resistance is 3 Ω.
Question 2.9
By which rule is the direction of rotation of Barlow’s wheel determined? [1]
Solution
The direction of rotation of Barlow’s wheel is determined by Fleming’s Left-Hand Rule.
Question 2.10
Mention one practical application of controlled chain reaction. [1]
OR
Why is a nuclear fission conducted before a nuclear fusion ? [1]
Solution
One practical application of a controlled chain reaction is in nuclear power plants.
OR
Nuclear fission is conducted before nuclear fusion because fission reactions release a large amount of energy that can be used to achieve the extremely high temperatures and pressures required for nuclear fusion to occur.
Question 2.11
Match the right column with the left column:
Left Column | Right Column |
(1) Noble Gas | (a) Cs |
(2) Inver | (b) Rn |
(3) Least electronegative element | (c) Reduction with carbon |
(4) ZnO + C → Zn + CO | (d) An alloy |
Solution
Left Column | Right Column |
(1) Noble Gas | (b) Rn |
(2) Inver | (d) An alloy |
(3) Least electronegative element | (a) Cs |
(4) ZnO + C → Zn + CO | (c) Reduction with carbon |
Question 2.12
KCl is soluble in which of water and benzene ? [1]
Solution
KCl is soluble in water but insoluble in benzene.
Question 2.13
In which electrode docs oxidation take place during electrolysis of water ? [1]
OR
Which one between AC and DC is used in electrolysis ? [1]
Solution
During the electrolysis of water, oxidation takes place at the anode.
OR
DC (Direct Current) is used in electrolysis.
Question 2.14
Why does an aqueous solution of HCl gas conduct electricity?
Solution
An aqueous solution of HCl gas conducts electricity because HCl dissociates into hydrogen ions (H⁺) and chloride ions (Cl⁻) when dissolved in water. These ions are charged particles that can move, allowing the solution to conduct electricity.
Question 2.15
Write the name and formula of an organic fertiliser produced from ammonia. [1]
OR
Write down the formula of the black precipitate formed when H2S gas is passed through an aqueous solution of silver nitrate.
Solution
Organic Fertilizer produced from ammonia:
Name: Urea
Formula: CO(NH2)2
OR
Black Precipitate formed when H2S gas is passed through an aqueous solution of silver nitrate:
The black precipitate formed is silver sulfide.
Formula: Ag2S
Question 2.16
Which compound is used to prepare melamine ? [1]
Solution
The compound used to prepare melamine is urea.
Question 2.17
Write down the names of two organic compounds with different functional groups designated by the formula C2H6O. [1]
Solution
Two organic compounds with the formula C₂H₆O but different functional groups are:
- Ethanol (alcohol) – CH3CH2OH
- Ether (dimethyl ether) – CH3OCH3
Question 2.18
Write down the structural formula of the principal constituent of LPG. [1]
OR
Write down the structural formula of 1, 1, 2, 2 tetrabromoethane. [1]
Solution
The principal constituent of LPG (Liquefied Petroleum Gas) is propane. The structural formula of propane is:
CH3CH2CH3
OR
The structural formula of 1,1,2,2-tetrabromoethane is:
CHBr2-CHBr2
Group – C
Answer the following questions (alternatives are to be noted):
Question 3.1
Write down the formula of Fire ice. How is methane gas obtained from it ?[1+1]
Solution
Fire ice is the common name for methane hydrate.
Chemical formula: CH4·nH2O
Methane gas is obtained from fire ice by heating or by reducing pressure.
Question 3.2
A certain amount of gas occupies 750 cc at – 3°C. The gas is heated at constant pressure till its volume becomes 1 litre. What is its final temperature? [2]
OR
What will be the volume of 8 g of H2 gas (H=1)at a pressure of 4 atmospheres and a temperature of 27℃? [R=0.082 litre atmosphere mole-¹K-¹]. [2]
Solution
Given
- V1 = 750 cc (initial volume)
- T1 = -3°C = 270 K (initial temperature in Kelvin)
- V2 = 1 litre = 1000 cc (final volume)
- T2 is the final temperature in Kelvin.
Using the formula:
750\over270 = 1000\over\text{T}_2
or, T2 = (1000 × 270) \over 750
T2 = 360 K
Converting T2 back to Celsius:
T2 = 360 K – 273 = 87°C
So, the final temperature is 87°C.
OR
Given
- Pressure (P) = 4 atm
- Volume = V (what we need to find)
- number of moles = n
- R = 0.082 L·atm·mol⁻¹·K⁻¹
- Temperature (T) = 27°C + 273 = 300 K
Number of moles (n) = 8\over2 = 4 mol
PV = nRT
or, 4 × V = 4 × 0.082 × 300
or, V = 4 × 0.082 × 300\over 4 = 24.6 L
So, the volume of 8 g of H₂ gas is 24.6 liters.
Question 3.3
At what angle must a light ray fall on the surface of an equilateral prism so that its angle of minimum deviation will be 20°? [2]
OR
Calculate the time required by a ray of light to traverse a glass slab of thickness 2 mm. The refractive index of glass=1.5. [2]
Solution
Angle of the prism = 60°
Angle of minimum deviation (δ) = 20°
We know,
Angle of minimum deviation (δ) = 2i – A
or, δ = 2i – A
or, 2i = δ + A = 20° + 60° = 80°
or, i = 40°
OR
Given
- Distance = 2 mm = 2 × 10⁻³ m
- Speed of light in vacuum (c) = 3 × 10⁸ m/s
- Refractive index of glass (μ) = 1.5
μ = \text{c}\over\text{v}
or, v = \text{c}\over\text{μ}
= \text{3 × 10⁸}\over\text{1.5}
= 2 × 10⁸ m/s
Question 3.4
Establish the relationship between internal resistance and EMF of an electric cell. [2]
Solution
Current (I) = \text{EMF}\over \text{Total Resistance}
Current (I) = \text{E}\over \text{(R + r)}
∴ E = I (R + r)
Question 3.5
Define the Octet rule. Give two examples of such compounds in which an exception to the Octet rule is observed. [1+1]
OR
Write two important differences between ionic and covalent compounds.
Solution
Octet Rule: Atoms tend to gain, lose, or share electrons to achieve 8 electrons in their outer shell.
Exceptions:
- BeCl2: Beryllium has 4 electrons in its outer shell.
- BF3: Boron has 6 electrons in its outer shell.
OR
The differences between ionic and covalent compounds:
Property | Ionic Compounds | Covalent Compounds |
---|---|---|
Bond Type | Transfer of electrons | Sharing of electrons |
Melting/Boiling Points | High melting/boiling points | Lower melting/boiling points |
Question 3.6
Why is the formula weight appropriately used instead of the molecular weight in the case of the ionic compounds? [2]
Solution
The formula weight is used for ionic compounds because they don’t consist of discrete molecules. Instead, they form a crystal lattice with repeating units, and the formula weight is the sum of the atomic weights of the ions in the formula unit. Molecular weight applies to covalent compounds, where discrete molecules exist.
Question 3.7
Why is concentrated H2SO4 not used to dry ammonia gas ? [2]
Solution
Concentrated H2SO4 is not used to dry ammonia gas because it reacts with ammonia to form ammonium bisulfate (NH4HSO4). This reaction absorbs the ammonia gas, making H2SO4 ineffective as a drying agent.
Question 3.8
Why is dehydrated calcium chloride added during the extraction of sodium through electrolysis of sodium chloride ? [2]
OR
Mention two ways of preventing the rusting of iron. [2]
Solution
Dehydrated calcium chloride (CaCl2) is added during the electrolysis of sodium chloride (NaCl) because it lowers the melting point of sodium chloride. Sodium chloride has a high melting point, and adding CaCl2 helps to keep the electrolyte in a molten state at lower temperatures, making the process more efficient.
OR
Two ways of preventing the rusting of iron:
- Galvanization: Coating iron with a layer of zinc to protect it from exposure to moisture and air.
- Paint coating: Applying a layer of paint to prevent direct contact between iron and the environment.
Question 3.9
What is a denatured spirit? [2]
OR
Write one use each of Ethyl alcohol and Acetic acid. [2]
Solution
Denatured spirit is ethanol (ethyl alcohol) that has been mixed with chemicals (denaturants) to make it undrinkable. This is done to avoid the consumption tax on alcohol while still allowing it to be used as a solvent or fuel.
OR
Uses:
- Ethyl alcohol: It is used as a solvent in industries and laboratories.
- Acetic acid: It is used in the production of vinegar for culinary purposes.
Group – D
4. Answer the following questions(alternatives are to be noted):
Question 4.1
Mention a phenomenon by which it can be said that the gas molecules are in constant motion. Mention two incorrect postulates of the Kinetic Theory of gas. [1+2]
Solution
Brownian motion/ Diffusion demonstrates the random movement of particles due to constant collisions with gas molecules.
Two incorrect postulates of the Kinetic Theory of Gas:
- Gas molecules do not interact (incorrect, as intermolecular forces exist).
- Gas molecules have perfectly elastic collisions (incorrect, as some energy is lost in collisions).
Question 4.2
How much H2 is obtained when steam is passed over 21 g red hot iron? What would be the volume of that H2 at STP? [Fe=56] [2+1]
OR
SO3 is prepared by oxidising SO2 in presence of O2. How much SO2 in grams will be required to produce 40 g of SO3? (S = 32, O = 16)
Solution
Balanced Eq: 3Fe + 4H2O → Fe3O4 + 4H2
. 3 × 56 g = 168 g 4 × 2 = 8 g
Amount of H2 produced by 168 g of Fe = 8 g
or, Amount of H2 produced by 21 g of Fe = 8\over168 × 21 g = 1 g
Volume of 2 g of H2 = 22.4 liters
∴ Volume of 1 g of H2 = 22.4 / 2 = 11.2 liters
OR
Balanced Eq: 2SO2 + O2 → 2SO3
. 64 g 32 g 80 g
To produce 80 g of SO3, 64 g of SO2 is required.
∴ To produce 40 g of SO3, 32 g of SO2 is required.
Question 4.3
Define Thermal conductivity. What is the SI unit of Thermal resistance? [2 + 1]
OR
Define volume expansion coefficient of a gas. Find its value from Charles’s law. [1 + 2]
Solution
Thermal Conductivity is the ability of a material to conduct heat. It indicates how easily heat passes through a substance.
The SI unit of Thermal Resistance is kelvin per watt (K/W). It measures how much a material resists the flow of heat.
OR
Volume expansion coefficient: The coefficient of volume expansion of a gas at constant pressure is defined as the fraction of its volume at 0°C by which the volume of a fixed mass of gas expands per degree Celsius rise in temperature.
According to Charles’ law, the volume of a given mass of gas at constant pressure expands or contracts by a fixed fraction 1/273 of its volume at 0°C for each degree Celsius rise or fall in temperature.
we get γₚ = 1 \over 273 °C-1
= 0.00366°C-1
Question 4.4
Write down the relationship between relative refractive index and absolute refractive index. On which factors does the relative refractive index of a medium depend? [1 + 2]
OR
Show that if a monochromatic light ray passes symmetrically through an equilateral prism then the angle of deviation of that ray will be minimum.
Solution
1μ2 = μ_2\over μ_1
Factors on which Relative Refractive Index depends:
- Wavelength of Light: The refractive index changes with the wavelength of light, leading to dispersion.
- Nature of the Media: The refractive index depends on the optical properties and composition of the two media involved.
Question 4.5
Define dispersion of light. How would you identify monochromatic light and composite light with the help of a prism? [1 + 2]
Solution
Dispersion of Light is the phenomenon where light splits into its constituent colors (spectrum) when passing through a medium, such as a prism.
Identifying Monochromatic and Composite Light with a Prism:
- Monochromatic Light: It passes through the prism without splitting, remaining as a single color.
- Composite Light: It splits into a spectrum of colors when passed through the prism.
If the light remains a single color, it’s monochromatic; if it spreads out into a rainbow, it’s composite light.
Question 4.6
The equivalent resistances of two conductors are 9 Ω and 2 Ω when they are connected in series and parallel combinations respectively. Find the resistances of those two conductors.
OR
Find the equivalent resistance between A and B points of the following circuit.
Solution
For Series: R1 + R2 = 9 or, R1 = 9 – R2 — (i)
For Parallel: 1\over R_\text{parallel} = 1\over R_1 + 1\over R_2
or, 1\over 2 = R_1×R_2\over R_1 + R_2
or, 1\over 2 = (9 - R_2)×R_2\over 9
or, 9R2 – R22 = 18
or, R22 – 9R2 – 18 = 0
or, R22 – (6 + 3)R2 – 18 = 0
or, R2(R2 – 6) – 3(R2 – 6) = 0
or, (R2 – 6)(R2 – 3) = 0
or, R2 = 6Ω or 3 Ω
Put R2 in eq (i) we get: R1 = 6Ω or 3 Ω
The resistances of the two conductors are 3Ω and 6Ω.
OR
The 2 Ω and 3 Ω resistors are connected in parallel.
1\over \text{R}_{\text{Parallel}}= 1\over \text{R}_1 + 1\over \text{R}_2
1\over \text{R}_{\text{Parallel}}= 1\over 2 + 1\over 3
1\over \text{R}_{\text{Parallel}}= 3 + 2\over 6 = 5\over 6
or, Rparallel = 6\over 5 = 1.2 Ω
∴ Rtotal = Rparallel + R3 = 1 Ω + 1.2 Ω = 2.2 Ω
Question 4.7
Write down the difference between dynamo and electric motor. What is earthing?
Solution
Difference between Dynamo and Electric Motor:
Feature | Dynamo | Electric Motor |
---|---|---|
Function | Converts mechanical energy into electrical energy (generator). | Converts electrical energy into mechanical energy. |
Operation | Works on the principle of electromagnetic induction (Faraday’s law). | Works on the principle of Lorentz force (interaction of magnetic field and current). |
Earthing is the process of connecting the electrical circuit or equipment to the ground (earth). It provides a safe path for the current to flow into the earth in case of a fault, reducing the risk of electrical shock and preventing damage to electrical devices.
Question 4.8
Compare the charge, penetrating power and ionising power of α and γ rays.
Solution
Comparison between α rays and γ rays based on charge, penetrating power, and ionising power:
Property | α Rays (Alpha Rays) | γ Rays (Gamma Rays) |
---|---|---|
Charge | Positive charge (+2) | No charge (neutral) |
Penetrating Power | Low penetration, stopped by a sheet of paper or skin | High penetration, can pass through thick materials like concrete and lead |
Ionising Power | High ionising power, can ionize atoms effectively | Low ionising power, but can still ionize atoms over long distances |
Question 4.9
What is meant by ionisation energy of an atom of an element? Arrange Na, Rb, Li and Cs in the increasing order of their ionisation energy.
OR
The atomic numbers of the elements ‘A’, ‘B’ and ‘C’ are (n-2), n, (n+1) respectively, ‘B’ is an inert gas. In which group of the Periodic Table are ‘A’ and ‘C’ located? Which one among them has the highest reductive power? What is the formula of the compound produced by combining ‘A’ and ‘C’?
Solution
Ionisation energy is the amount of energy required to remove an electron from an isolated atom in the gaseous state.
Rb < Cs < Na < Li
OR
Group of A and C:
- A (atomic number n-2) is in Group 1 (alkali metals).
- C (atomic number n+1) is in Group 17 (halogens).
Highest Reductive Power:
- A (an alkali metal) has the highest reductive power.
Formula of the Compound:
- The formula of the compound formed between A (Group 1) and C (Group 17) will be AC, such as NaCl, LiCl, etc.
Question 4.10
What is the purpose of Electro-plating? What electrolyte is used to plate gold on any substance?
Solution
The purpose of electroplating is:
- To improve the appearance of the surface.
- To provide protection against corrosion, wear, and tear.
To plate gold on a substance, the electrolyte used is typically a solution containing gold chloride (AuCl3) or gold cyanide (Au(CN)2⁻).
Question 4.11
Write the names of the chemicals used and the balanced chemical equation in the industrial production of urea.
Solution
Chemicals Used:
- Ammonia (NH3)
- Carbon dioxide (CO2)
Balanced Chemical Equation:
2NH3 + CO2 → NH2CONH2 + H2O
Question 4.12
Write down the reaction of the industrial production of Ethylene. Mention two uses of Ethylene.
OR
How is carbon tetrachloride produced by substituting the hydrogen atoms of methane by chlorine atoms in steps?
Solution
CH3CH2OH (Vapour) \overset {Al_2O_3,\ 350°C} {\longrightarrow} H2C = CH2 (Ethylene) + H2O
The two uses of Ethylene are:
- To ripen fruit and for fruit preservation.
- To make plastic polyethylene.
OR
Carbon tetrachloride (CCl₄) is produced by chlorinating methane (CH4) in several steps:
- CH4 + Cl2 → CH3Cl + HCl
- CH3Cl + Cl2 → CH2Cl2 + HCl
- CH2Cl2 + Cl2 → CHCl3 + HCl
- CHCl3 + Cl2 → CCl4 + HCl