Flash Education

Generic selectors
Exact matches only
Search in title
Search in content
Post Type Selectors
post
question

Madhyamik Class 9 Physical Science Formula

formula cover page
WhatsApp

System of Measurement and Measuring Devices

UNIT OF LENGTH:

Unit NameSymbolEquivalent in MetersConversions
Fermifm10-15 m1 fm = 10-15 m
AngstromÅ10-10 m1 Å = 105 fm
Nanometernm10-9 m1 nm = 10 Å 
Micrometerµm10-6 m1 µm = 1000 nm
Millimetermm10-3 m1 mm = 1000 µm
Centimetercm10-2 m1 cm = 10 mm
Meterm1 m1 m = 100 cm
Kilometerkm103 m1 km = 1000 m
Astronomical UnitAU1.496 × 1011 m1 AU = 1.496 × 108 km
Light Yearly9.461 × 1015 m9.461 × 1012 km
Parsecpc3.086 × 1016 m1 pc = 3.26 ly

UNIT OF MASS:

  • 1 metric ton (MT) = 10 quintal (q) = 10³ kg = 10⁶ g = 10⁹ mg
  • 1 amu = mass of 1 atom of C¹²

UNIT OF TIME:

NameSymbolIn Seconds (s)Conversions
Millisecondms10-3 s1 ms = 0.001 s
Seconds1 s1 min = 60 s
Minutemin60 s1 hr = 60 min
Hourhr3600 s1 day = 24 hr
Dayd86,400 s1 week = 7 days
Weekwk604,800 s1 month ≈ 4.3 weeks
Monthmo2.63 × 106 s1 year = 12 months
Yearyr3.154 × 107 s1 decade = 10 years
Decade3.154 × 108 s1 century = 10 decades
Century3.154 × 109 s1 millennium = 10 centuries
Millennium3.154 × 1010 s1 millennium = 1000 1000 years

UNIT OF VOLUME:

Unit NameSymbolIn Cubic Meters (m³)Conversions
Cubic Centimetercm³10−6 m31 cm3 = 1 mL
MillilitermL10−6 m3 mL = 11 cm3
Cubic Decimeterdm³10−3 m31 dm3 = 1000 cm3 = 1 L
LiterL10−3 m31 L = 1000 mL = 1 dm3

UNIT OF DENSITY:

  • Density = mass / volume
  • g/cc or g/cm³ or kg/m³ or kgm⁻³

MEASUREMENT OF MASS USING COMMON BALANCE

(i) Unequal arm length but same scale pan weight:

Mass on left pan × Length of left arm = Mass on right pan × Length of right arm

(ii) Equal arm length but unequal scale pan weight:

True weight, W = (W₁ + W₂) / 2,

where W₁ and W₂ are counterpoise weights in two scale pans.

(iii) Unequal arm lengths and unequal scale pan weights:

True weight, W = √(W₁ × W₂),

where W₁ and W₂ are counterpoise weights in two scale pans.

ERROR CALCULATION

(i) Absolute error = | True value – Measured value |

(ii) Relative error = \text{absolute error}\over \text{measured value}

(iii) Percentage error = Relative error × 100 %

Force and Motion

Distance

  1. Formula: Distance = Speed × time
  2. Unit: metre (m) in SI and cm in CGS
  3. It is a scalar quantity.

Speed

  1. Formula: Speed = \text {Distance}\over \text { time}
  2. Avg Speed = \text {Total Distance}\over \text {Total time}
  3. Unit: metre/second  (m/s) in SI and cm/s in CGS
  4. It is a scalar quantity.

Displacement

  1. Formula: Displacement = velocity × time
  2. Unit: metre (m) in SI and cm in CGS
  3. It is a vector quantity.

Velocity

  1. Formula: Velocity = \text {Displacement}\over \text { time}
  2. Avg Velocity = \text {Total Displacement}\over \text {Total time}
  3. Unit: metre/second  (m/s) in SI and cm/s in CGS
  4. It is a vector quantity.

Acceleration

  1. Formula: Acceleration = \text{v – u}\over \text{t}
  2. Unit: metre/second2  (m/s2) in SI and cm/s2 in CGS
  3. It is a vector quantity

Equation of Motion

  1. v = u + at
  2. s = ut + 1/2 at2
  3. v2 = u2 + 2as
  • u = initial velocity
  • v = Final velocity
  • a = acceleration
  • s = displacement
  • t = time

Law of parallelogram of forces

The magnitude and direction of the resultant R is given by:

(a) R = P + Q and is parallel to P and Q when θ = 0°.

(b) R = |P – Q| and is directed along the larger of the two forces when θ = 180°.

(c) R = √(P² + Q²) and is directed along the diagonal of the rectangle having P and Q as adjacent sides, i.e. θ = 90°.

Momentum

(i) Momentum (p) = Mass (m) × velocity (v)

(ii) Initial momentum = Mass (m) × Initial velocity (u)

(iii) Final momentum = Mass (m) × Final velocity (v)

(iv) Change of momentum (Δp) = m (v – u)

(v) Rate of Change of momentum = m (v – u)/t

Force

(i) Force (F) = mass (m) × acceleration (a)

(ii) Force (F) = m (v – u)/t

Recoil velocity of gun (V) = – \text {m}\ over \text {M} v

  • m = mass of bullet
  • v = mass of velocity
  • M = Mass of gun

Pressure of liquid and Air

(i) Thrust (F) = Pressure (P) × Area (A)

(ii) Liquid Pressure (P) = h × d × g

  • h = depth of the point
  • d = density of liquid
  • g = acceleration due to gravity

(iii) Atmospheric pressure (PA) = h × dHg × g

  • h = height of mercury column
  • dHg = density of mercury
  • g = acceleration due to gravity

(iv) Upthrust (F) = V × d × g

  • V = volume of solid body
  • d = density of liquid in which the solid body is immersed
  • M = Vd = mass of liquid having same volume as the solid body
  • W = weight of the displaced liquid

(v) Density (d) = \text {Mass} \over \text {volume}

(vi) Relative density (RD) = \text {Weight of the substance} \over \text {weight of an equal volume of water at 4ºC}

(vii) Bernoulli’s theorem : In a steady flow, the sum of all forms of energy in a fluid is the same at all points that are free of viscous forces.

potential energy + kinetic energy + pressure energy = constant

hg + 1/2V2 + p/d = constant

(viii) Stress (S) = Force/Area

(ix) Young’s Modulus (Y) = \text {Longitudinal stress} \over \text {Longitudinal strain} = {\text {F} \over \text {A}} × {\text {L} \over \text {ΔL}} 

where

  • L = original length
  • ΔL = change in length

Atomic Structure, the Physical and Chemical Properties of Matter

Atomic structure

An element X having mass number A and atomic number Z is symbolically represented as or ZXA.

(i) Number of proton = A

(ii) Number of electron = A

(iii) Number of Neutron = A – Z

Concept of Mole

(i) Number of moles = \text{Given mass}\over \text{Molecular mass}

(ii) Number of moles = \text{Given Volume}\over \text{22.4}

(iii) Number of moles = \text{Number of particles}\over 6.022 × 10^23

Solution

Solubility = \text{weight of solute (in g)}\over \text{weight of solvent (in g)} × 100

Work, Power, Energy

(i) Work (W) = Force (F) × displacement (d)

(ii) Power

(a) Power (P) = Work/time

(b) Power (P) = Force (F) × velocity (v)

(iii) Potential Energy (Ep) = m × g × h

  • m = mass of the body
  • g = acceleration due to gravity
  • h = height above the ground

(iv) Kinetic energy (Ek) = 1\over2 mv2

(v) Work (W) =  1\over2 mv21\over2 mu2

Heat

Fundamental principle of calorimetry :

(i) Heat lost by hot bodies = Heat gained by cold bodies

(ii) m1 × s1 × (t1 – t) = m2 × s2 × (t – t2)

Heat necessary to raise the temperature of a body: 

(ii) Heat (Q) = m × s × t

Where,

  • m = mass of body
  • s = specific heat of material
  • t = change in temperature

(iii) Thermal capacity :

(a) Formula : C = m s

(b) Unit : cal/ °C or J/K

(iv) Work (W) = Joule constant (J) × Heat (H)

(v) Heat (Q) = mass (m) × Specific Latent heat (L)

Sound

(i) Relation between time period and frequency of wave :

(a) Time Period (T) = 1\over \text{frequency (f)}

(b) Frequency (f) = 1\over \text{Time Period (T)}

(ii) Velocity (v) = frequency (f) × wavelength (λ)

(iii) Depth of sea = \text{velocity × time}\over 2

(iv) Height (H) = \text{t√(V2 – v2)}\over 2

Where

  • V = Velocity of sound in air
  • v = velocity of aeroplane
  • t = time difference between sound and its echo
Close Menu
error: Content is protected !! 💀
Index