Madhyamik Class 10 Physical Science Question Paper Solved 2019

Madhyamik Physical Science 2019
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Madhyamik Class 10 Physical Science Question Paper Solved 2019

PHYSICAL SCIENCE

Time: 3 Hours 15 Minutes

(First 15 Minutes for reading the question paper only, 3 Hours for writing) 

Full Marks: For Regular Candidates – 90

For External Candidates – 100


(For Regular & External Candidates)

Only the External Candidates will answer Group ‘E’. Figures in the margin indicate full marks for each question.


Group ‘A’

1. Multiple choice question. [1 × 15 = 15]

Question 1.1.

Which among the following gases absorb long wavelength infrared radiation emitted from the earth’s surface?

  1. N2
  2. O2
  3. CH4
  4. He

Solution

c. CH4 (Methane)

Explanation: Greenhouse gases like methane (CH₄) absorb long-wavelength infrared radiation emitted by the Earth’s surface, trapping heat in the atmosphere.

Question 1.2.

At STP, 2.24 ltr is occupied by

  1. 4.4 g CO2
  2. 0.64 g SO2
  3. 28 g CO
  4. 16 g O2

Solution

a. 4.4 g CO2

Explanation: 

4.4 g CO2:

Molar mass of CO2 = 44 g/mol

Moles of CO2 = 4.4 / 44 = 0.1 mol

Volume = 0.1 × 22.4  = 2.24 L

Question 1.3.

How many molecules of CO2 will be produced when one mole C reacts completely with one mole O2?

  1. 6.022 × 1023
  2. 1.806 × 1024
  3. 6.022 × 1022
  4. 6.022 × 1024

Solution

a. 6.022 × 10²³

Question 1.4.

For a solid, how many types of thermal expansion coefficients are there?

  1. 1
  2. 2
  3. 3
  4. 4

Solution

c. 3

Explanation: For a solid, there are three types of thermal expansion coefficients:

  • Linear expansion coefficient
  • Area expansion coefficient
  • Volumetric expansion coefficient

Question 1.5.

Which one of the following has the highest wavelength?

  1. x-ray
  2. γ-ray
  3. infrared ray
  4. Ultraviolet ray

Solution

c. Infrared ray

Question 1.6.

In case of refraction, if the angle of incidence and the angle of refraction are 45° and 30° respectively, then the angle of deviation is

  1. 75°
  2. 15°
  3. 7.5°
  4. 37.5°

Solution

b. 15°

Explanation:

The angle of deviation (δ) in refraction is given by the formula:

δ = Angle of incidence − Angle of refraction

Here, the angle of incidence is 45° and the angle of refraction is 30°. So,

δ = 45 ° − 30 ° = 15°

Question 1.7.

Temperature remains unchanged if the potential difference between the two ends of a conductor is V and the current through the conductor is I, which of the following is true?

  1. V ∝ I
  2. V ∝ I²
  3. V ∝ I-1
  4. V ∝ I -2

Solution

a. V ∝ I

Explanation: Ohm’s Law states that the current (I) flowing through a conductor between two points is directly proportional to the potential difference (V)

V = IR

Question 1.8.

The relation among electromotive force (V), work (W) and charge (Q) is

  1. Q=WV
  2. Q=V/W
  3. Q=V/W²
  4. Q=W/V

Solution

d. Q = W/V

Question 1.9.

For the atom produced by β-particle emission from a radioactive atom

  1. mass number increases
  2. atomic number increases
  3. mass number decreases
  4. atomic number decreases

Solution

b. Atomic number increases

Explanation: During β-particle emission (β-decay), a neutron in the nucleus of a radioactive atom is converted into a proton, emitting a β-particle (an electron) and an antineutrino. This process increases the atomic number of the atom by 1.

Question 1.10.

To which group of the long periodic table do the halogen elements belong?

  1. Group 1
  2. Group 16
  3. Group 17
  4. Group 2

Solution

c. Group 17

Explanation: The halogen elements belong to Group 17 of the long periodic table. They are characterized by having seven electrons in their outermost electron shell.

Question 1.11.

Solid state of which of the following compounds is composed of ions?

  1. sodium chloride
  2. hydrogen chloride
  3. naphthalene
  4. glucose

Solution

a. Sodium chloride

Explanation: Sodium chloride (NaCl) is an ionic compound, and its solid state is composed of a regular arrangement of ions (sodium ions and chloride ions) held together by ionic bonds.

Question 1.12.

Which of the following has the highest ability to conduct electricity?

  1. pure water
  2. aqueous solution of sugar
  3. liquid HCl
  4. aqueous solution of acetic acid

Solution

c. Liquid HCl

Explanation: Liquid HCl (hydrochloric acid) has the highest ability to conduct electricity among the options given. This is because it is a strong acid that dissociates completely into ions in its liquid state, providing a high concentration of ions that can conduct electricity.

Question 1.13.

In the first step of fixation of nitrogen which of the following compounds is formed as a result of lightning?

  1. NO
  2. NO2
  3. N2O5
  4. HNO3

Solution

NO

Explanation: During lightning, the high energy breaks the nitrogen (N2) and oxygen (O2) molecules in the atmosphere, leading to the formation of nitrogen monoxide (NO). This is a key step in the nitrogen fixation process that converts atmospheric nitrogen into compounds that can be used by living organisms.

Question 1.14.

Which of the following is the formula of bauxite, ore of aluminium?

  1. Al2O3
  2. Al2O3.H2O
  3. Al2O3.2H2O
  4. AlF3.3NaF

Solution

c. Al2O3.2H2O

Explanation: Bauxite, the primary ore of aluminium, is commonly represented by the formula Al2O3·2H2O, indicating it is an aluminium oxide hydrate. The specific form of bauxite can vary, but it generally contains aluminium oxide combined with water.

Question 1.15.

Which of the following is the alkyl group containing two carbon atoms?

  1. methyl
  2. ethyl
  3. propyl
  4. isopropyl

Solution

b. Ethyl

Explanation: The ethyl group is the alkyl group containing two carbon atoms. Its formula is C2H5.

  • Methyl is a one-carbon alkyl group (CH3).
  • Propyl has three carbon atoms (C3H7).
  • Isopropyl is a branching form of propyl, also containing three carbon atoms.

Group-B

2. Answer the following question (alternatives are to be noted).

Question 2.1

Write down the unit of calorific value of fuel. [1]

OR

Does the temperature increase or decrease with an increase in altitude in the stratosphere? [1]

Solution

The unit of calorific value of fuel is Joules per kilogram (J/kg) or kilocalories per kilogram (kcal/kg).

OR

In the stratosphere, the temperature increases with an increase in altitude.

Question 2.2

Which radiation, coming from the sun, is prevented by the ozone layer from falling on the earth’s surface? [1]

Solution

The ozone layer prevents ultraviolet (UV) radiation from reaching the Earth’s surface.

Question 2.3

State whether the following statement is true or false. [1]

The volume of gas molecules is taken into consideration in Avogadro’s law.

Solution

False.

Question 2.4

The product of volume and pressure of how many grams of N2 gas is 224 litre-atmospheres at STP? [N = 14]  [1]

Solution 

Number of moles = 224\over 22.4 = 10 mole

Mass = Number of moles × Molar mass

= 10 × 28

= 280 grams

Question 2.5

Whether the following statement is true or false?

The constituent’s particles of a material change position during the conduction of heat through it. [1]

OR

The width and the cross-section of a conductor remain unchanged, what is the relation between the thermal resistance and thermal conductivity of that conductor? [1]

Solution

False

Explanation: During the conduction of heat through a material, the constituent particles (atoms or molecules) do not change their position. Instead, heat is transferred through the vibration or movement of these particles within their fixed positions.

OR

The relation between thermal resistance (Rth ​) and thermal conductivity (k) of a conductor is given by:

Rth = L/kA

Question 2.6

What will be the angle of incidence when a ray of light passes through the centre of curvature of a concave mirror? [1]

Solution

When a ray of light passes through the center of curvature of a concave mirror, the angle of incidence is 0 degrees.

Question 2.7

How many rectangular surfaces are there in a prism? [1]

Solution

A prism has 3 rectangular surfaces.

Question 2.8

Give an example of a semiconductor. [1]

Solution

Silicon is a common example of a semiconductor.

Question 2.9

A thin wire and a thick wire of the same conducting material have the same length. Which one of them will carry more current when connected to the same potential difference? [1]

Solution

The thick wire will carry more current when connected to the same potential difference.

Question 2.10

Mention one misuse of the nuclear fission reaction. [1]

OR

Which law explains the release of huge amounts of energy in nuclear fusion? [1]

Solution

Misuse of Nuclear Fission Reaction:

One misuse of nuclear fission reactions is in the creation of nuclear weapons.

OR

The release of a huge amount of energy in nuclear fusion is explained by Einstein’s mass-energy equivalence principle, which is given by the equation:

E=mc2

Question 2.11

Match the right column with the left column: [1 × 4 = 4]

Left Column Right Column
1. The oxide layer protects from attack by the water vapour a) Cu
2. Group-1 element of the long periodic
table having the least reduced power
b) Be
3. When the metal remains exposed
to air, the metal slowly develops
green patches on its surface
c) Al
4. Group 2 element of the long periodic table having the least atomic radius d) Li

 

Solution

  1. c) Al
  2. d) Li
  3. a) Cu
  4. b) Be

Question 2.12

Draw the Lewis dot structure of the N2 molecule, (N = 7). [1]

Solution

Lewis dot structure of the N2 molecule

Electron Dot structure of Nitrogen

Question 2.13

Which kind of electricity is used in electrolysis? [1]

OR

Write down the cathode reaction in the electrolysis of acidulated water using platinum electrodes. [1]

Solution

Direct current (DC) electricity is used in electrolysis.

OR

Cathode Reaction in the Electrolysis of Acidulated Water Using Platinum Electrodes:

2H2O + 2e → H2 + 2OH

This reaction produces hydrogen gas at the cathode.

Question 2.14

In electroplating gold on brass, what is the electrolyte used? [1]

Solution

In electroplating gold on brass, the electrolyte used is typically a gold chloride solution or gold cyanide solution.

Question 2.15

What colour is formed in the reaction of ammonia with Nessler’s reagent? [1]

Solution

The reaction of ammonia with Nessler’s reagent forms a yellow or brown colour.

Question 2.16

Write down the formula of the precipitate formed when H2S gas is passed through an aqueous solution of silver nitrate. [1]

OR

Write the name of the compound which is formed by the reaction of nitrogen with magnesium metal at a high temperature. [1]

Solution 

The formula of the precipitate formed when HS gas is passed through an aqueous solution of silver nitrate is Ag2S (silver sulfide).

OR

The compound formed by the reaction of nitrogen with magnesium metal at a high temperature is magnesium nitride.

Question 2.17

What is the value of the H-C-H bond angle in methane? [1]

OR

Write the IUPAC name of CH3CH2COOH. [1]

Solution

The H-C-H bond angle in methane is 109.5°.

OR

The IUPAC name of CH3CH2COOH is propanoic acid.

Question 2.18

What is the industrial source of CNG? [1]

Solution

The industrial source of CNG (Compressed Natural Gas) is natural gas, which primarily consists of methane (CH4).

Group ‘C’

3. Answer the following questions. [2 × 9 = 18]

Question 3.1

What is the concept of sustainable development? [2]

Solution

Sustainable development aims to meet current needs without compromising the ability of future generations to meet theirs. It balances:

  1. Environmental Sustainability: Protecting natural resources and ecosystems.
  2. Economic Sustainability: Ensuring equitable economic growth.
  3. Social Sustainability: Improving quality of life and ensuring social equity.

Question 3.2

1 g of a gas at 7°C and 2 atmosphere pressure occupies a volume of 410 ml. Determine the molar mass of the gas. (R = 0.082 litre atmosphere mole-1 K-1)

OR

A fixed mass of gas occupies a volume of 273 cm³ at STP. At what pressure the above gas will occupy a volume of 300 cm³ at 27°C? [2]

Solution

Pressure (P) = 2 atm

Volume (V) = 410 ml = 0.410 L

Temperature (T) = 7ºC = 280 K

R = 0.082 L atm mol −1 K −1

Use the Ideal Gas Law: PV = (m/M) RT

⇒ M = RT\over mPV

⇒ M = 1  × 0.082 × 280\over 2 × 0.410

⇒ M = 28 g/mol

OR

Initial Pressure (P1)= 1 atm

Initial volume (V1) = 273 cm3

initial temperature (T1) = 273 K (STP)

Final volume (V2) = 300 cm3

Final temperature (T2) = 300 K

From Combined Gas Equation: P_1V_1\over T_1P_2V_2\over T_2

P2 = P_1V_1T_2\over T_1V_2

P2 = 1 × 273 × 300\over 273 × 300 = 1 atm

Thus, the pressure is 1 atm.

Question 3.3

What is the refractive index of a medium? [2]

OR

Which type of defect of vision is rectified by a convex lens? [2]

Solution

The refractive index of a medium is a measure of how much the speed of light is reduced when it passes through the medium compared to its speed in a vacuum. It is defined as the ratio of the speed of light in a vacuum (c) to the speed of light in the medium (v):

n = c/v

OR

A convex lens is used to correct hyperopia (farsightedness). In this condition, the eye focuses light behind the retina instead of on it, causing distant objects to be seen more clearly than nearby objects. A convex lens converges the light rays, helping focus them correctly on the retina.

Question 3.4

Two resistances r1 and r2, when connected separately to the same potential difference, it was seen that the current flowing through r1 was 6 times the current flowing through r2. Determine the ratio of r1 and r2. [2]

Solution

We are given that the current through r1 ​ is 6 times the current through r2 ​ when connected to the same potential difference.

Using Ohm’s Law:

I = V/R

Let the current through r1 ​ be I1 ​ and through r2 ​ be  I2

According to the question,

I1 = 6 × I2

⇒ V/r1 = 6 × V/r2

⇒ 1/r1 = 6 × 1/r2

⇒ r1/r2 = 1/6

So, the ratio of r1 and r2 is 1 : 6

Question 3.5

How does Kossel explain the formation of ionic bond? [2]

OR

Liquid hydrogen chloride can not conduct electricity, but molten sodium chloride can conduct electricity. Explain. [2]

Solution

Kossel explained that an ionic bond forms due to the complete transfer of electrons from one atom (usually a metal) to another atom (usually a non-metal). This process leads to the formation of oppositely charged ions: the metal loses electrons to become a positively charged cation, and the non-metal gains electrons to become a negatively charged anion. The electrostatic attraction between these oppositely charged ions holds them together in an ionic bond.

OR

Liquid Hydrogen Chloride vs Molten Sodium Chloride in Conducting Electricity:

  • Liquid hydrogen chloride (HCl) does not conduct electricity because, in its liquid form, HCl consists of neutral molecules. There are no free ions available to carry an electric current.
  • Molten sodium chloride (NaCl) can conduct electricity because, when melted, the strong ionic bonds break, and the solid NaCl dissociates into free-moving Na+ and ions. These free ions allow the molten NaCl to conduct electricity as they can move and carry the electric charge.

Question 3.6

Distinguish between sodium chloride and naphthalene by two physical properties. [2]

Solution

Properties Sodium chloride Naphthalene
Melting Point Has a high melting point (around 801°C). Has a low melting point (around 80°C)
Solubility Highly soluble in water Insoluble in water

Question 3.7

Between two aqueous solutions, one is ferric chloride and the other is aluminium chloride. How would you identify the ferric chloride solution using an aqueous solution of ammonia? Answer with a balanced chemical equation. [2]

Solution

When ferric chloride reacts with aqueous ammonia, a reddish-brown precipitate of ferric hydroxide (Fe(OH)3) forms.

Balanced chemical equation

FeCl3 + 3NH4OH → Fe(OH)↓ + 3NH4Cl

When aluminium chloride (AlCl3) reacts with aqueous ammonia, a white precipitate of aluminium hydroxide (Al(OH)3) forms.

AlCl3 + 3NH4OH → Al(OH)↓ + 3NH4Cl

Question 3.8

Why zinc blende can be called both mineral and ore of zinc? [2]

OR

Mention two ways of preventing the rusting of iron. [2]

Solution

Zinc blende (ZnS) can be called both a mineral and an ore of zinc because:

  • Mineral: Zinc blende is called a mineral because it is a naturally occurring crystalline substance.
  • Ore: Zinc blende is also classified as an ore of zinc because zinc can be economically extracted from it.

OR

Two ways to prevent the rusting of iron:

  1. Galvanization: Coating iron or steel with a layer of zinc to protect it from rusting.
  2. Painting or Coating: Applying a layer of paint or other protective coatings (such as plastic) on the iron surface to create a barrier against moisture and oxygen, thus preventing rust formation.

Question 3.9

Write with a balanced chemical equation what happens when methane is burnt in oxygen. [2]

OR

Mention one use of each of acetic acid and ethyl alcohol. [2]

Solution

When methane (CH4) is burnt in oxygen (O2), it undergoes a combustion reaction, producing carbon dioxide (CO), and water (H2O), and releasing energy in the form of heat and light.

Balanced chemical equation

CH4 ​+ 2O2 ​→ CO2 ​+ 2H2​O

One use of each:

  1. Acetic acid: It is used as a key ingredient in vinegar, which is commonly used in cooking and food preservation.
  2. Ethyl alcohol (Ethanol): It is used in the preparation of alcoholic beverages.

Group ‘D’

4. Answer the following questions.

Question 4.1

What is meant by the molar volume of a gas? Mention two reasons for the deviation of real gasses from the behaviour of ideal gases. [1 + 2]

Solution

The molar volume of a gas is the volume occupied by one mole of the gas at standard temperature and pressure.

Two reasons for the deviation are

Reason Real Gases Ideal Gas
Intermolecular Forces Real gases experience attractive forces between molecules Ideal gases experience no attractive forces between molecules
Molecular Volume Real gas molecules occupy a finite volume. Ideal gases are considered to have point-sized particles with no volume

 

Question 4.2

How many grams of Al is required to prepare 558 g of Fe by the reduction of Fe2O3 With Al at high temperature? How many moles of Fe2O3 are required in the reaction? (F = 55.8, Al = 27, O = 16) 

[2 + 1]

OR

By heating 32.1 gram ammonium chloride with calcium hydroxide 10.2 g NH3, 33.3 g CaCl2, and 10.8 g H2O are obtained. How many grams of calcium hydroxide take part in the reaction? How many moles of NH3, and how many litre of NH3 at STP are formed in the reaction? (N=14, H=1)

[1 + 2]

Solution

Balanced Chemical Equation

Fe2​O3​ + 2Al → 2Fe + Al2​O3​

1 mole   54 g    111.6 g

Calculation of Aluminium

Quantity of Al required to produce 111.6 g of Fe = 54 g

∴ Quantity of Al required to produce 558 g of Fe

= 54\over 111.6 × 558

= 270 g

Calculation of mole of Fe2O3

Mole of Fe2​O3​ required to produce 111.6 g of Fe = 1 mole

∴ Mole of Fe2​O3​ required to produce 558 g of Fe = 1\over 111.6 × 558

= 5

OR

Balanced Chemical Equation:

2NH4​Cl  + Ca(OH)2​ → 2NH3 ​+ CaCl2 ​+ 2H2​O

107 g             74 g               34 g       111g

Moles of NH3 produced

Molar mass of NH3 = 17 g

Mass of NH3 = 10.2 g

Moles of NH3 = 10.2/17 = 0.6

Volume of NHat STP:

Volume = 0.6 × 22.4 = 13.44 L

Mass of Ca(OH)2 Used:

Molar mass of Ca(OH)2 = 74 g

From the equation, 1 mole Ca(OH)2 produces 2 moles NH₃.

So for 0.6 moles NH3:

Moles of Ca(OH)2 = 0.6/2 = 0.3 moles

Mass of Ca(OH)2 = 0.3 × 74 = 11.1 g

Summary

  • Mass of Ca(OH)₂ used: 11.1 g
  • Moles of NH₃ produced: 0.6 moles
  • Volume of NH₃ at STP: 13.44 liters

Question 4.3

Which quantities remain fixed in the definition of the volume expansion coefficient of a gas? Name a non-metal which is a good conductor of heat. [2 + 1]

OR

What is meant by ‘the linear expansion coefficient of copper is 17 × 10-6 °C-1? Why does the value remain the same even in the Kelvin scale? [2 + 1]

Solution

The volume expansion coefficient (α) of a gas is defined as the fractional change in volume per unit change in temperature at constant pressure. Therefore, the quantity that remains fixed in this definition is:

Pressure (constant pressure is maintained).

Graphite, a form of carbon, is a non-metal that is an excellent conductor of heat.

OR

The linear expansion coefficient of copper, 17 × 10⁻⁶ °C⁻¹, means that for every 1°C rise in temperature, the length of a copper object increases by 17 × 10⁻⁶ times its original length. This describes how much a material expands per degree of temperature change.

A change of 1°C is equal to a change of 1 K, so the rate of expansion per unit temperature change is the same in both scales.

Question 4.4

What type of mirror is used by the dentists? Why a ray of light does not deviate as a result of refraction through a glass slab? [1 + 2]

Solution

Dentists use a concave mirror.

Refraction of through glass slab:

Ray_Diagram_-removebg-preview

When a ray of light passes through a glass slab, it undergoes refraction twice: once when entering the glass and once when exiting. The refraction at the second surface is such that the ray emerges parallel to its original path. This happens because the angle of incidence and refraction are equal but opposite at both surfaces, resulting in no overall deviation in the direction of the light ray. However, the ray is displaced laterally.

Question 4.5

When an object is placed 20 cm away from a convex lens, no image is obtained on either side of the lens. What is the focal length of the lens? If the refractive index of glass with respect to air is 1.5, what is the refractive index of air with respect to glass? [2 + 1]

OR

The length of an object is 5 cm. An image of length 10 cm is obtained when it is placed at distance of 2 cm in front of a convex lens. What is the linear magnification and image distance? [1 + 2]

Solution

If no image is obtained when an object is placed 20 cm away from a convex lens, it suggests that the object is at the focus of the lens. This means the object distance (u) is equal to the focal length (f) of the lens. Therefore, the focal length of the lens is:

f = 20 cm

glassnair = 1/1.5 = 0.67

Thus, the refractive index of air with respect to glass is 0.67.

OR

The linear magnification () of a lens is the ratio of the image size to the object size. Given:

  • Object length = 5 cm
  • Image length = 10 cm

m = Image\ size\over Object\ size = 10\over 5 = 2

So, the linear magnification is 2.

Image Distance:

Magnification (m) = 2

Object distance (u) = – 2 cm

v = m × u = 2 × (-2) = -4 cm

So, the image distance is -4 cm (negative indicating the image is on the same side as the object, meaning it’s a virtual image).

Question 4.6

Write in brief the basic principal of hydro-electric power generation. [3]

Solution

Hydro-electric power generation is based on the principle of converting potential energy of stored water into kinetic energy and then into electrical energy. The basic steps are:

  1. Water Storage: Water is stored at a height in reservoirs behind a dam. This water has potential energy due to its elevated position.
  2. Water Flow and Turbines: When released, the water flows through pipes (penstocks), and its potential energy is converted into kinetic energy. The flowing water strikes and rotates turbines connected to a generator.
  3. Electricity Generation: The rotating turbines drive the generator, converting mechanical energy into electrical energy, which is then distributed for use.

Question 4.7

A current of 1 A flows when an electric bulb is connected to 220 V mains. What could be the current when the same bulb is connected to 110V mains? [3]

OR

Find the ratio of resistance for two bulbs of 220V-60W and 110V-60W. [3]

Solution

Initial voltage (V1) = 220 V

Current (I1) = 1 A

Voltage for the second case (V2) = 110 V

Resistance (R) of the bulb:

R = V_1\over I_1 = 220\over 1 = 220 Ω

Current in the second case:

I2 = V_2\over R = 110\over 220 = 0.5 A

OR

The formula for power: P = V^2\over R

For the first bulb (220V-60W):

R1 = V^2\over P = 220^2\over 60 = 806.67 Ω

For the second bulb (110V-60W):

R2 = V^2\over P = 110^2\over 60 = 201.67 Ω

Now, find the ratio of their resistances:

Required Ratio = R_1\over R_2 = 806.67\over 201.67 = 4

Thus, the ratio of resistance for the two bulbs is 4:1.

Question 4.8

Explain why a new element is formed by α-particle emission but no new element is formed by γ-ray emission from a radioactive element. [2 + 1]

Solution

An α-particle consists of 2 protons and 2 neutrons. When emitted, the nucleus loses 2 protons, reducing the atomic number by 2 and the mass number by 4, forming a new element that is two places lower in the periodic table.

γ-ray emission only releases energy without changing the number of protons or neutrons. Since the atomic number remains unchanged, no new element is formed.

Question 4.9

Write down Dobereiner’s law of triads. Arrange Cl, Br, I, and F in increasing order of their oxidising power. [2 + 1]

OR

What is the important conclusion of Moseley’s experiment? What is the importance of this conclusion in regard to periodic table? [2 + 1]

Solution

Dobereiner’s law of triads states that in a group of three elements (a triad) with similar chemical properties, the atomic mass of the middle element is approximately the arithmetic mean of the atomic masses of the other two elements.

The oxidizing power of these halogens increases as follows:

I < Br < Cl < F

OR

Important Conclusion of Moseley’s Experiment

Moseley’s experiment established that the atomic number (not atomic mass) defines an element’s identity, as X-ray frequencies corresponded to atomic numbers.

Importance of the Periodic Table

This led to the periodic table being organized by atomic number rather than atomic mass, resolving previous inconsistencies and accurately reflecting element properties.

Question 4.10

Write two differences between the conduction of electricity through a metallic and an electrolyte during electrolysis. In electrolytic refining of copper metal, impure copper rod is used as which electrode? [2 + 1] 

Solution

Metallic Conduction Electrolytic Conduction

Electricity is conducted through the movement of free electrons in metals.

Electricity is conducted through the movement of ions in a liquid or molten electrolyte.

Conductivity occurs in solid metals.

Conductivity occurs in liquids or molten salts.

In electrolytic refining of copper, the impure copper rod is used as the anode.

Question 4.11

Write the names of the chemicals used and balanced chemical equation in the industrial production of urea. [3]

Solution

Chemicals Used in Industrial Production of Urea

  1. Ammonia (NH3)
  2. Carbon Dioxide (CO2)

Balanced Chemical Equation

2NH3 ​ + CO2 ​ →NH2 CONH2 ​+ H2O

In this reaction, ammonia and carbon dioxide react to form urea and water.

Question 4.12

(A) and (B) are two unsaturated hydrocarbons, each containing two carbon atoms. On reaction with bromine, (A) adds one molecule of bromine per molecule and (B) adds two molecules of bromine per molecule. Write structural formula of (A) and (B). Write balanced chemical equation of reaction of (B) with bromine. [2 + 1]

OR

Write balanced chemical equation of the reaction of sodium hydroxide with acetic acid. Which one between jute and polythene is environment friendly for packaging and why? [1 + 2]

Solution

Structural Formulas

(A): Since (A) adds one molecule of bromine per molecule, it must be an alkene with the general formula C2H4.

The structural formula of (A) is:

Ethene: CH2 ​=CH2

(B): Since (B) adds two molecules of bromine per molecule, it must be an alkene with the general formula C2H2​.

The structural formula of (B) is:

Ethyne: HC≡CH

Balanced Chemical Equation for (B) with Bromine

HC ≡ CH + 2Br2 → CHBr2 − CHBr2

In this reaction, ethyne reacts with two molecules of bromine to form 1, 2 – dibromoethane

OR

Balanced Chemical Equation:

NaOH + CH3​COOH → CH3​COONa + H2​O

Jute is more environmentally friendly for packaging compared to polythene. This is because jute is a natural, biodegradable fiber that decomposes quickly, while polythene is a synthetic plastic that can take hundreds of years to break down, contributing to environmental pollution.

Group ‘E’

[For External Candidates Only]

5. Answer the following questions (any four):[1×4 =4]

Question 5.1

Give an example of non-conventional energy with the help of which electricity can be generated.

Solution

Solar energy is a non-conventional energy source used to generate electricity.

Question 5.2

Write the Sl unit of electric power.

Solution

The SI unit of electric power is the watt (W).

Question 5.3

Which acid is manufactured utilising catalytic oxidation of ammonia?

Solution

Nitric acid (HNO3) is manufactured using the catalytic oxidation of ammonia.

Question 5.4

At STP an ideal gas occupies a volume of 273 cm³. What volume will the gas occupy at 76 cm Hg pressure and at a temperature of 273℃?

Solution

Initial volume (V1 ) = 273 cm³

Initial pressure (P1) = 1 atm = 760 mm Hg

Initial temperature (T1) = 273 K (which is 0°C)

Final pressure (P2) = 76 mm Hg

Final temperature (T2) = 273°C = 546 K

Apply the Combined Gas Law: P_1V_1\over T_1=P_2V_2\over T_2

760 × 273\over 273=76 × V_2\over 546

⇒ V2 =760 × 273 ×  546\over 273 × 76

⇒ V2 = 5460 cm³

Thus, the volume of the gas at 76 mm Hg pressure and 273°C is approximately 5460 cm³.

Question 5.5

What is the functional group present in ethyl alcohol?

Solution

The functional group present in ethyl alcohol (ethanol) is the hydroxyl group (−OH)

6. Answer the following questions (any three): [2×3 =6]

Question 6.1

What is a superconductor?

Solution

A superconductor is a material that can conduct electricity with zero electrical resistance.

Example: Mercury below 4.2 K, and lead below 7.25 are superconductors.

Question 6.2

Mention one use of each of ultraviolet rays and gamma rays.

Solution

UV rays are used to kill microorganisms in water and on surfaces.

Gamma rays are used in cancer treatment and medical imaging.

Question 6.3

Write the name and formula of one ore of iron.

Solution

One ore of iron is hematite. Its chemical formula is Fe2O3.

Question 6.4

Write mentioning the product, how the polymerisation reaction of ethylene is carried out.

Solution

Polymerisation of ethylene: Ethylene is liquified at high pressure (1500-2000 atm). In the presence of catalysts such as peroxide, oxygen or chromium oxide and at temperatures 150℃-200℃, a large number of ethylene molecules join to form a white solid called polyethylene or polythene.

nC2​H4​→(C2​H4​​)n

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