| Time in (s) | Body (A) | Body (B) | Body (C) |
| 1stSecond | 20 | 20 | 20 |
| 2ndSecond | 20 | 36 | 60 |
| 3rdSecond | 20 | 24 | 100 |
| 4thSecond | 20 | 30 | 140 |
| 5thSecond | 20 | 48 | 180 |
(i) (a) Body A (b) Body C (c) Body B (ii) (a) Body C. Total distance travelled = 100 – 60 = 40 cm (b) Body B. Total distance travelled…
Observe the graph carefully and answer the following questions. (i) Which part of the graph shows the squirrel moving away from the tree? (ii) Name the point on the graph which is 6 m away from the base of the tree. (ii) Which part of the graph shows that the squirrel is not moving? (iv) Which part of the graph shows that the squirrel is returning to the tree? (v) Calculate the speed of the squirrel from the graph during its journey.(i) Part AB (ii) Part B (iii) Part BC (iv) Part CD (v) Total distance travelled 6 m + 6 m = 12 m Time = 11 s. Speed =…
Velocity from 0 to 50 s is 𝑣1 = = 2 ms-1 Velocity from 50 s to 100 s, 𝑣2 = = - 2 ms-1 Accordingly the velocity-time graph is…
Speed = Slope of distance-time graph. The smaller the slope, the smaller is the speed. From the figure, slope is minimum for car D. So, D is the slowest car.
For train A, the initial velocity, u = 54 kmh-1 = 54 × = 15 ms-1 Final velocity, v = 0 and time, t = 5s For train B,…
We know the upward motion, u2 = u2 -2gh Or h = But at the highest point, v = 0 Therefore, h = For first ball, h1 = and for…
Using the equation of motion s = Distance travelled in 5 seconds, s = Or s = .......(1) Similarly, distance travelled in 4 seconds, s' = ....(2) Distance travelled…
(i) Consider a body which starts with initial velocity u and due to uniform acceleration a, its final velocity becomes v after time t. Then, its average velocity is given…
Consider the velocity-time graph of an object that moves under uniform acceleration as shown in the figure (u ≠ O). From this graph, we can see that initial velocity of…
The nature of the graph shows that velocity changes by equal amounts in equal intervals of time. For a uniformly accelerated motion, velocity-time graph is always a straight line. As…