Question

A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement-time graph is shown in figure. Plot a velocity-time graph for the same.

  • Motion CBSE Class 9
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Answer

Velocity from 0 to 50 s is ๐‘ฃ1 ={\bigtriangleup s \over \bigtriangleup t} = {100 - 0 \over50 - 10} = 2 ms-1

Velocity from 50 s to 100 s, ๐‘ฃ2 ={\bigtriangleup s \over \bigtriangleup t} = {0 - 100 \over100 - 50} = – 2 ms-1

Accordingly the velocity-time graph is shown in figure below.

time velocity

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