Given, 500 ml. of gas ‘X’ at s.t.p. weighs 0.50 g
Therefore, 1000 ml of gas ‘X’ at s.t.p. will weigh (0.50 x 2) g
Vapour density of gas X
= Wt\ of\ 1000\ ml\ of\ gas\ at\ STP\over Wt\ of\ 1000\ ml\ of\ H_2\ at\ STP
= 0.50 × 2\over 0.09
=11.1
Hence, vapour density of gas is 11.11
Molecular weight = 2 × Vapour density
= 2 x 11.1
= 22.2 g
Hence, molecular weight of gas is 22.2 g