Mass = 0.20 kg
Initial velocity = 20ms-1
KE = 1\over 2 × mass × (velocity)2
= 1\over 2 × 0.20 × (20)2
= 1\over 2 × 0.20 × 400
= 40 J
∴ Maximum potential energy at the maximum height = Initial kinetic energy = 40 J
Question
A ball of mass 0.20 kg is thrown vertically upwards with an initial velocity of 20 ms-1. Calculate the maximum potential energy it gains as it goes up.
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