F = 100 N
h = 3m
displacement = 5m
We know,
(i) Work done = Force × displacement in the direction of the force
= 100 × 5
= 500 J
(ii) The potential energy gained by the block U = mgh or F×h
= 100 × 3
= 300 J
(iii) The difference (200 J) energy is used in doing work against the force of friction between the block and the slope and it will appear as heat energy.
(a) What is the work done by the force F in moving the block A, 5m along the slope? (b) What is the increase in potential energy of the block A? (c) Account for the difference in the work done by the force and the increase in potential energy of the block.
(a) Calculate the change in the gravitational potential energy of the skier between A and B. (b) If 75% of the energy in part (a) becomes the kinetic energy at B, calculate the speed at which the skier arrives at B.(Take g = 10 ms-2).