Mass (m) = 7.5 kg
(a) Force (F) = 7.5 × 10 = 75 N
Hence, F = 75 N
(b) Area of the base = 12 × 8
= 96 cm2
= 0.0096 m2
Pressure (P) = Force/Area
= 75/0.0096
= 750000/96
= 7812.5 Pa
Question
A block of iron of mass 7.5 kg and of dimensions 12 cm x 8 cm x 10 cm is kept on a table top on it’s base of side 12 cm x 8 cm. Calculate (a) thrust and (b) pressure exerted on the table top. Take 1 kgf = 10 N.
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